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In a single throw of a pair of different dice. Find the probability of getting A prime number on each dice A total of 9 or 11
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In a single throw of a pair of different dice. Find the probability of...
As we throw two die we have 6^2 i.e 36 chances
So n(S) = 36
Let the event A be having prime on each dice
So chances are {(2,2), (2,3), (2,5), (3,2), (3,3), (3,5), (5,2), (5,3), (5,5)}
Hence n(A) = 9
Thus P(A) = 9/36 = 1/4
Let B be the event having the sum of 9 or 11
So chances will be like {(3,6), (6.3), (4.5), (5,4), (5,6), (6,5)}
So n(B) = 6
Thus P(B) = 6/36 = 1/6
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In a single throw of a pair of different dice. Find the probability of...
Probability of Getting a Prime Number on Each Die

To find the probability of getting a prime number on each die, we need to determine the total number of possible outcomes and the number of favorable outcomes.

Total Number of Possible Outcomes:
When throwing a pair of dice, each die has 6 sides, numbered from 1 to 6. Since the dice are different, we can consider the two dice separately. Therefore, the total number of possible outcomes is the product of the number of outcomes on each die, which is 6 * 6 = 36.

Number of Favorable Outcomes:
To determine the number of favorable outcomes, we need to identify the prime numbers on a die. Prime numbers are numbers greater than 1 that have no divisors other than 1 and themselves. On a die, the prime numbers are 2, 3, and 5.

Probability of Getting a Prime Number on Each Die:
To find the probability of getting a prime number on each die, we divide the number of favorable outcomes by the total number of possible outcomes.

Number of favorable outcomes = 3 (since there are 3 prime numbers on a die)
Total number of possible outcomes = 36

Probability of getting a prime number on each die:
Probability = Number of favorable outcomes / Total number of possible outcomes
Probability = 3 / 36
Probability = 1 / 12

Therefore, the probability of getting a prime number on each die is 1/12.

Probability of Getting a Total of 9 or 11:
Now we need to calculate the probability of getting a total of 9 or 11 when throwing the pair of dice.

Number of Favorable Outcomes:
To find the number of favorable outcomes, we need to identify all the possible combinations of numbers on the two dice that sum up to 9 or 11.

For a total of 9, the possible combinations are:
- (3, 6)
- (4, 5)
- (5, 4)
- (6, 3)

For a total of 11, the possible combinations are:
- (5, 6)
- (6, 5)

Therefore, the number of favorable outcomes is 6.

Probability of Getting a Total of 9 or 11:
To find the probability of getting a total of 9 or 11, we divide the number of favorable outcomes by the total number of possible outcomes.

Total number of possible outcomes = 36 (as calculated before)

Probability of getting a total of 9 or 11:
Probability = Number of favorable outcomes / Total number of possible outcomes
Probability = 6 / 36
Probability = 1 / 6

Therefore, the probability of getting a total of 9 or 11 when throwing a pair of dice is 1/6.
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In a single throw of a pair of different dice. Find the probability of getting A prime number on each dice A total of 9 or 11
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