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A fair six-sided die is rolled twice. What is the probability of getting 2 on the first roll and not getting 4 on the second roll?
  • a)
    1/36
  • b)
    1/18
  • c)
    5/36
  • d)
    1/6
  • e)
    1/3
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
A fair six-sided die is rolled twice. What is the probability of getti...
The two events mentioned are independent. The first roll of the die is independent of the second roll. Therefore the probabilities can be directly multiplied.
P(getting first 2) = 1/6
P(no second 4) = 5/6
Therefore P(getting first 2 and no second 4) = 1/6* 5/6 = 5/36
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Most Upvoted Answer
A fair six-sided die is rolled twice. What is the probability of getti...
Solution:

The probability of getting 2 on the first roll is 1/6.

The probability of not getting 4 on the second roll is 5/6.

The probability of both events happening together is (1/6) × (5/6) = 5/36.

Therefore, the probability of getting 2 on the first roll and not getting 4 on the second roll is 5/36.

Hence, option C is the correct answer.
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Community Answer
A fair six-sided die is rolled twice. What is the probability of getti...
Getting 2 on first dies has probability 1/6 and not getting 4 on the dies is 5/6 so answer is 5/36
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A fair six-sided die is rolled twice. What is the probability of getting 2 on the first roll and not getting 4 on the second roll?a)1/36b)1/18c)5/36d)1/6e)1/3Correct answer is option 'C'. Can you explain this answer?
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