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What will happen when Young's double slit apparatus is immersed in liquid of denser medium? (Hint: Think of wavelength and Fringe width)Answer This.?Board 2014 CBSE?

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What will happen when Young's double slit apparatus is immersed in liq...
When immersed in denser medium refractive index increase so wavelength decrease. so fringe width decrease bcoz it is directly proportional to wavelength
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What will happen when Young's double slit apparatus is immersed in liq...
Effect of Immersing Young's Double Slit Apparatus in a Denser Medium
When Young's double slit apparatus is immersed in a denser medium, several changes occur due to the properties of light and its interaction with different media.
Change in Wavelength
- The wavelength of light decreases in a denser medium.
- The relation is given by the formula:
- Wavelength in the medium = Wavelength in vacuum / Refractive index of the medium.
Change in Fringe Width
- The fringe width (β) is given by the formula:
- β = λD/d, where λ is the wavelength, D is the distance from the slits to the screen, and d is the distance between the slits.
- As the wavelength decreases in the denser medium, the fringe width also decreases. This means that the distance between the bright and dark fringes on the screen will become smaller.
Visual Appearance of the Fringe Pattern
- The overall fringe pattern will appear more compressed.
- The bright and dark fringes will be closer together, making it harder to distinguish individual fringes.
Conclusion
- Immersing Young's double slit apparatus in a denser medium leads to a decrease in the wavelength of light.
- Consequently, the fringe width also decreases, resulting in a denser fringe pattern on the observation screen. This phenomenon illustrates how the optical properties of light can change with the medium it propagates through, affecting interference patterns significantly.
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What will happen when Young's double slit apparatus is immersed in liquid of denser medium? (Hint: Think of wavelength and Fringe width)Answer This.?Board 2014 CBSE?Please let me know if you want the answer. Anyone can message to know the answer?
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