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Vm reveals the turnover number (kcat) of an enzyme if [Et] is known what is value of Kcat_____×105
sec–1.
if [Et] = 1 µM and Vm = 600 mols/L/sec, Kcat = ?
sec–1.
if [Et] = 1 µM and Vm = 600 mols/L/sec, Kcat = ?
Correct answer is '6'. Can you explain this answer?
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Vm reveals the turnover number (kcat) of an enzyme if [Et] is known wh...
Explanation:
The turnover number (kcat) of an enzyme is defined as the number of substrate molecules converted to product per enzyme molecule per unit time when the enzyme is saturated with substrate. The unit of kcat is sec-1.
Given:
[Et] = 1 M
Vm = 600 mols/L/sec
kcat = ?
We can use the following formula to calculate kcat:
kcat = Vm/[Et]
where Vm is the maximum velocity of the enzyme-catalyzed reaction, and [Et] is the total enzyme concentration.
Substituting the given values, we get:
kcat = 600 mols/L/sec / 1 M
kcat = 600 sec-1
Rounding off to the nearest integer, we get:
kcat = 6
Therefore, the value of kcat is 6.
Conclusion:
The turnover number (kcat) of an enzyme can be calculated from the maximum velocity (Vm) and the total enzyme concentration ([Et]). In this case, the value of kcat is 6 when [Et] is 1 M and Vm is 600 mols/L/sec.
The turnover number (kcat) of an enzyme is defined as the number of substrate molecules converted to product per enzyme molecule per unit time when the enzyme is saturated with substrate. The unit of kcat is sec-1.
Given:
[Et] = 1 M
Vm = 600 mols/L/sec
kcat = ?
We can use the following formula to calculate kcat:
kcat = Vm/[Et]
where Vm is the maximum velocity of the enzyme-catalyzed reaction, and [Et] is the total enzyme concentration.
Substituting the given values, we get:
kcat = 600 mols/L/sec / 1 M
kcat = 600 sec-1
Rounding off to the nearest integer, we get:
kcat = 6
Therefore, the value of kcat is 6.
Conclusion:
The turnover number (kcat) of an enzyme can be calculated from the maximum velocity (Vm) and the total enzyme concentration ([Et]). In this case, the value of kcat is 6 when [Et] is 1 M and Vm is 600 mols/L/sec.
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Vm reveals the turnover number (kcat) of an enzyme if [Et] is known what is value of Kcat_____×105sec–1.if [Et] = 1 µM and Vm = 600 mols/L/sec, Kcat = ?Correct answer is '6'. Can you explain this answer?
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Vm reveals the turnover number (kcat) of an enzyme if [Et] is known what is value of Kcat_____×105sec–1.if [Et] = 1 µM and Vm = 600 mols/L/sec, Kcat = ?Correct answer is '6'. Can you explain this answer? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about Vm reveals the turnover number (kcat) of an enzyme if [Et] is known what is value of Kcat_____×105sec–1.if [Et] = 1 µM and Vm = 600 mols/L/sec, Kcat = ?Correct answer is '6'. Can you explain this answer? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Vm reveals the turnover number (kcat) of an enzyme if [Et] is known what is value of Kcat_____×105sec–1.if [Et] = 1 µM and Vm = 600 mols/L/sec, Kcat = ?Correct answer is '6'. Can you explain this answer?.
Vm reveals the turnover number (kcat) of an enzyme if [Et] is known what is value of Kcat_____×105sec–1.if [Et] = 1 µM and Vm = 600 mols/L/sec, Kcat = ?Correct answer is '6'. Can you explain this answer? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about Vm reveals the turnover number (kcat) of an enzyme if [Et] is known what is value of Kcat_____×105sec–1.if [Et] = 1 µM and Vm = 600 mols/L/sec, Kcat = ?Correct answer is '6'. Can you explain this answer? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Vm reveals the turnover number (kcat) of an enzyme if [Et] is known what is value of Kcat_____×105sec–1.if [Et] = 1 µM and Vm = 600 mols/L/sec, Kcat = ?Correct answer is '6'. Can you explain this answer?.
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