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Two point charges +q and -q are held fixed at (-d,0) and (d,0) respectively of a x-y coordinate system. Then
- a)The electric field E at all points on x-axis has the same direction.
- b)Electric field at all point on y-axis is along x-axis.
- c)Work has to be done in bringing a test charge from ∞ the origin.
- d)The dipole moment is 2qd along the x-axis.
Correct answer is option 'B'. Can you explain this answer?
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Two point charges +q and -q are held fixed at (-d,0) and (d,0) respect...
Infinity to any point on the x-axis.
d)The potential at the point (0,a) is zero.
e)The electric field at the origin is zero.
a) True: Since the electric field due to a point charge is radial and points away from the charge, the electric fields due to the two charges q and -q will point in opposite directions along the x-axis. Therefore, the electric field at all points on the x-axis will have the same direction.
b) True: Since the y-axis passes through the midpoint of the two charges, the electric fields due to the two charges will cancel out along the y-axis. Therefore, the electric field at all points on the y-axis will be along the x-axis.
c) True: Work has to be done in bringing a test charge from infinity to any point on the x-axis because the electric field is nonzero at all points on the x-axis due to the presence of the two fixed charges. Therefore, the test charge experiences a force and work is done against this force to bring the test charge to the x-axis.
d) False: The potential at the point (0,a) is not zero. The potential due to a point charge q at a distance r from the charge is given by V = kq/r, where k is the Coulomb constant. Therefore, the potential at the point (0,a) due to the charge q at (-d,0) is V = kq/(a+d), and the potential at the point (0,a) due to the charge -q at (d,0) is V = -kq/(a-d). The total potential at the point (0,a) is the sum of these two potentials, which is nonzero unless d=a.
e) False: The electric field at the origin is not zero. The electric field due to a point charge q at a distance r from the charge is given by E = kq/r^2, where k is the Coulomb constant. Therefore, the electric field at the origin due to the charge q at (-d,0) is E = kq/d^2, and the electric field at the origin due to the charge -q at (d,0) is E = -kq/d^2. The total electric field at the origin is the sum of these two fields, which is zero if q is zero or if d is infinity.
d)The potential at the point (0,a) is zero.
e)The electric field at the origin is zero.
a) True: Since the electric field due to a point charge is radial and points away from the charge, the electric fields due to the two charges q and -q will point in opposite directions along the x-axis. Therefore, the electric field at all points on the x-axis will have the same direction.
b) True: Since the y-axis passes through the midpoint of the two charges, the electric fields due to the two charges will cancel out along the y-axis. Therefore, the electric field at all points on the y-axis will be along the x-axis.
c) True: Work has to be done in bringing a test charge from infinity to any point on the x-axis because the electric field is nonzero at all points on the x-axis due to the presence of the two fixed charges. Therefore, the test charge experiences a force and work is done against this force to bring the test charge to the x-axis.
d) False: The potential at the point (0,a) is not zero. The potential due to a point charge q at a distance r from the charge is given by V = kq/r, where k is the Coulomb constant. Therefore, the potential at the point (0,a) due to the charge q at (-d,0) is V = kq/(a+d), and the potential at the point (0,a) due to the charge -q at (d,0) is V = -kq/(a-d). The total potential at the point (0,a) is the sum of these two potentials, which is nonzero unless d=a.
e) False: The electric field at the origin is not zero. The electric field due to a point charge q at a distance r from the charge is given by E = kq/r^2, where k is the Coulomb constant. Therefore, the electric field at the origin due to the charge q at (-d,0) is E = kq/d^2, and the electric field at the origin due to the charge -q at (d,0) is E = -kq/d^2. The total electric field at the origin is the sum of these two fields, which is zero if q is zero or if d is infinity.
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Two point charges +q and -q are held fixed at (-d,0) and (d,0) respect...
Hiii...so basically
A. Direction must be changing as distance from the two point charges is kept changing.
B. yeah its true direction is always along the x axis.
C.Electric potential at the origin cancels off and hence no need to do work to move it from infinity.
D. Dipole moment basically has a different formulam.m Cheers!!!
A. Direction must be changing as distance from the two point charges is kept changing.
B. yeah its true direction is always along the x axis.
C.Electric potential at the origin cancels off and hence no need to do work to move it from infinity.
D. Dipole moment basically has a different formulam.m Cheers!!!
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Two point charges +q and -q are held fixed at (-d,0) and (d,0) respectively of a x-y coordinate system. Thena)The electric field E at all points on x-axis has the same direction.b)Electric field at all point on y-axis is along x-axis.c)Work has to be done in bringing a test charge from ∞ the origin.d)The dipole moment is 2qd along the x-axis.Correct answer is option 'B'. Can you explain this answer?
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Two point charges +q and -q are held fixed at (-d,0) and (d,0) respectively of a x-y coordinate system. Thena)The electric field E at all points on x-axis has the same direction.b)Electric field at all point on y-axis is along x-axis.c)Work has to be done in bringing a test charge from ∞ the origin.d)The dipole moment is 2qd along the x-axis.Correct answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Two point charges +q and -q are held fixed at (-d,0) and (d,0) respectively of a x-y coordinate system. Thena)The electric field E at all points on x-axis has the same direction.b)Electric field at all point on y-axis is along x-axis.c)Work has to be done in bringing a test charge from ∞ the origin.d)The dipole moment is 2qd along the x-axis.Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two point charges +q and -q are held fixed at (-d,0) and (d,0) respectively of a x-y coordinate system. Thena)The electric field E at all points on x-axis has the same direction.b)Electric field at all point on y-axis is along x-axis.c)Work has to be done in bringing a test charge from ∞ the origin.d)The dipole moment is 2qd along the x-axis.Correct answer is option 'B'. Can you explain this answer?.
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