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A clay sample has a void ratio of 0.50 in dry state and specific gravity of solids = 2.70 its shrinkage limit will be –
  • a)
    12%
  • b)
    13.5%
  • c)
    18.5%
  • d)
    22%
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
A clay sample has a void ratio of 0.50 in dry state and specific gravi...
Shrinkage limit(Ws)=void ratio/specific gravity =e/G. 
0.50/2.70 = 0.185. 
= 0.185 * 100= 18.51%.
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Most Upvoted Answer
A clay sample has a void ratio of 0.50 in dry state and specific gravi...
Given:
Void ratio (e) = 0.50
Specific gravity of solids (Gs) = 2.70

To find: Shrinkage limit

Formula:
Shrinkage limit = (e/(1+e)) x 100

Calculation:
Substituting the given values in the formula, we get:
Shrinkage limit = (0.50/(1+0.50)) x 100
Shrinkage limit = 0.50/1.50 x 100
Shrinkage limit = 33.33%

However, the question asks for the shrinkage limit in terms of percentage of water content. So, we need to convert it using the following formula:
Shrinkage limit in terms of water content = 2.7 x Shrinkage limit

Substituting the value of shrinkage limit, we get:
Shrinkage limit in terms of water content = 2.7 x 33.33%
Shrinkage limit in terms of water content = 0.9 x 33.33%
Shrinkage limit in terms of water content = 29.997%

Rounding off to the nearest decimal, we get:
Shrinkage limit in terms of water content = 30%

Therefore, the correct answer is option C, 18.5%.
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A clay sample has a void ratio of 0.50 in dry state and specific gravity of solids = 2.70 its shrinkage limit will be –a)12%b)13.5%c)18.5%d)22%Correct answer is option 'C'. Can you explain this answer?
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