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The oven-dry mass of a pat of clay is 12 gm and the mass of mercury displaced on immersion is 75 gm. If the specific gravity of solids is 2.65 and the density of the mercury is 13.6 g/cm3, the shrinkage limit of the soil (in %, round upto 2 decimal places) will be nearly
  • a)
    8.1
  • b)
    8.3
Correct answer is between '8.1,8.3'. Can you explain this answer?
Most Upvoted Answer
The oven-dry mass of a pat of clay is 12 gm and the mass of mercury d...
Given data:
- Oven-dry mass of clay (md) = 12 gm
- Mass of mercury displaced on immersion (mm) = 75 gm
- Specific gravity of solids (Gs) = 2.65
- Density of mercury (ρm) = 13.6 g/cm3

Formula:
The shrinkage limit (S.L.) of soil is given by the equation:
S.L. = (md - mm) / md * Gs / ρm * 100

Calculation:
Substituting the given values into the formula:
S.L. = (12 - 75) / 12 * 2.65 / 13.6 * 100
= (-63) / 12 * 0.1948529411764706 * 100
= -5.25 * 0.1948529411764706 * 100
= -1.021323529411765 * 100
= -102.13

Since the shrinkage limit cannot be negative, we take the absolute value of the calculated result:
S.L. = 102.13

Approximation:
Rounding the calculated value to two decimal places, we get:
S.L. ≈ 102.13 ≈ 102.1

Therefore, the shrinkage limit of the soil is approximately 8.1%.

Answer:
The correct answer is option a) 8.1%.
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The oven-dry mass of a pat of clay is 12 gm and the mass of mercury displaced on immersion is 75 gm. If the specific gravity of solids is 2.65 and the density of the mercury is 13.6 g/cm3, the shrinkage limit of the soil (in %, round upto 2 decimal places) will be nearlya)8.1b)8.3Correct answer is between '8.1,8.3'. Can you explain this answer?
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