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A(s)=2B(g) C(g) The above equilibrium was established by taking A(s) only. At equilibrium B is removed so that it's partial pressure at new equilibrium becomes 1/3 of original total pressure. Ratio of total pressure at new equilibrium and at initial equilibrium will be?
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A(s)=2B(g) C(g) The above equilibrium was established by taking A(s) o...
Ans is 1/3 bcz after removing b only c left for eqlbm cons.so it's partial pressure is equal to total pressure at that time
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A(s)=2B(g) C(g) The above equilibrium was established by taking A(s) o...
The given equilibrium reaction is:
A(s) ⇌ 2B(g) + C(g)
The equilibrium was established by taking only A(s). This means that initially, there was only A(s) present and no B(g) or C(g).
Now, B(g) is removed from the system, and we need to determine the new equilibrium conditions.
Let's analyze the changes that occur when B(g) is removed:
1. Removal of B(g):
- Since B(g) is being removed, the reaction will shift to the left to compensate for the loss of B(g).
- As a result, the concentration of A(s) will increase, and the concentrations of B(g) and C(g) will decrease.
2. Partial pressure of B at new equilibrium:
- We are given that the partial pressure of B at the new equilibrium is 1/3 of the original total pressure.
- This means that the concentration of B(g) at the new equilibrium is 1/3 of the original concentration.
Now, let's determine the ratio of total pressure at the new equilibrium to the initial equilibrium:
1. Initial equilibrium:
- At the initial equilibrium, only A(s) is present.
- Since A(s) is a solid, its concentration does not change, and its partial pressure is negligible.
- Therefore, the total pressure at the initial equilibrium is solely due to B(g) and C(g).
2. New equilibrium:
- At the new equilibrium, B(g) and C(g) are present.
- We know that the partial pressure of B at the new equilibrium is 1/3 of the original total pressure.
- Since the initial equilibrium only consisted of B(g) and C(g), the total pressure at the new equilibrium will be 1/3 of the initial total pressure.
In conclusion, the ratio of the total pressure at the new equilibrium to the initial equilibrium is 1/3.
A(s) ⇌ 2B(g) + C(g)
The equilibrium was established by taking only A(s). This means that initially, there was only A(s) present and no B(g) or C(g).
Now, B(g) is removed from the system, and we need to determine the new equilibrium conditions.
Let's analyze the changes that occur when B(g) is removed:
1. Removal of B(g):
- Since B(g) is being removed, the reaction will shift to the left to compensate for the loss of B(g).
- As a result, the concentration of A(s) will increase, and the concentrations of B(g) and C(g) will decrease.
2. Partial pressure of B at new equilibrium:
- We are given that the partial pressure of B at the new equilibrium is 1/3 of the original total pressure.
- This means that the concentration of B(g) at the new equilibrium is 1/3 of the original concentration.
Now, let's determine the ratio of total pressure at the new equilibrium to the initial equilibrium:
1. Initial equilibrium:
- At the initial equilibrium, only A(s) is present.
- Since A(s) is a solid, its concentration does not change, and its partial pressure is negligible.
- Therefore, the total pressure at the initial equilibrium is solely due to B(g) and C(g).
2. New equilibrium:
- At the new equilibrium, B(g) and C(g) are present.
- We know that the partial pressure of B at the new equilibrium is 1/3 of the original total pressure.
- Since the initial equilibrium only consisted of B(g) and C(g), the total pressure at the new equilibrium will be 1/3 of the initial total pressure.
In conclusion, the ratio of the total pressure at the new equilibrium to the initial equilibrium is 1/3.
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A(s)=2B(g) C(g) The above equilibrium was established by taking A(s) only. At equilibrium B is removed so that it's partial pressure at new equilibrium becomes 1/3 of original total pressure. Ratio of total pressure at new equilibrium and at initial equilibrium will be?
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A(s)=2B(g) C(g) The above equilibrium was established by taking A(s) only. At equilibrium B is removed so that it's partial pressure at new equilibrium becomes 1/3 of original total pressure. Ratio of total pressure at new equilibrium and at initial equilibrium will be? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about A(s)=2B(g) C(g) The above equilibrium was established by taking A(s) only. At equilibrium B is removed so that it's partial pressure at new equilibrium becomes 1/3 of original total pressure. Ratio of total pressure at new equilibrium and at initial equilibrium will be? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A(s)=2B(g) C(g) The above equilibrium was established by taking A(s) only. At equilibrium B is removed so that it's partial pressure at new equilibrium becomes 1/3 of original total pressure. Ratio of total pressure at new equilibrium and at initial equilibrium will be?.
A(s)=2B(g) C(g) The above equilibrium was established by taking A(s) only. At equilibrium B is removed so that it's partial pressure at new equilibrium becomes 1/3 of original total pressure. Ratio of total pressure at new equilibrium and at initial equilibrium will be? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about A(s)=2B(g) C(g) The above equilibrium was established by taking A(s) only. At equilibrium B is removed so that it's partial pressure at new equilibrium becomes 1/3 of original total pressure. Ratio of total pressure at new equilibrium and at initial equilibrium will be? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A(s)=2B(g) C(g) The above equilibrium was established by taking A(s) only. At equilibrium B is removed so that it's partial pressure at new equilibrium becomes 1/3 of original total pressure. Ratio of total pressure at new equilibrium and at initial equilibrium will be?.
Solutions for A(s)=2B(g) C(g) The above equilibrium was established by taking A(s) only. At equilibrium B is removed so that it's partial pressure at new equilibrium becomes 1/3 of original total pressure. Ratio of total pressure at new equilibrium and at initial equilibrium will be? in English & in Hindi are available as part of our courses for Class 12.
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A(s)=2B(g) C(g) The above equilibrium was established by taking A(s) only. At equilibrium B is removed so that it's partial pressure at new equilibrium becomes 1/3 of original total pressure. Ratio of total pressure at new equilibrium and at initial equilibrium will be?, a detailed solution for A(s)=2B(g) C(g) The above equilibrium was established by taking A(s) only. At equilibrium B is removed so that it's partial pressure at new equilibrium becomes 1/3 of original total pressure. Ratio of total pressure at new equilibrium and at initial equilibrium will be? has been provided alongside types of A(s)=2B(g) C(g) The above equilibrium was established by taking A(s) only. At equilibrium B is removed so that it's partial pressure at new equilibrium becomes 1/3 of original total pressure. Ratio of total pressure at new equilibrium and at initial equilibrium will be? theory, EduRev gives you an
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