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A short bar magnet placed in a horizontal plane has its axis aligned along the magnetic north-south direction. Null points are found on the axis of the magnet at 14 cm from the centre of the magnet. The earth’s magnetic field at the place is 0.36 G and the angle of dip is zero. What is the total magnetic field on the normal bisector of the magnet at the same distance as the null–point (i.e., 14 cm) from the centre of the magnet? (At null points, field due to a magnet is equal and opposite to the horizontal component of earth’s magnetic field.)
- a)0.64 G in the direction of earth’s field.
- b)0.62 G in the direction of earth’s field.
- c)0.54 G in the direction of earth’s field.
- d)0.58 G in the direction of earth’s field.
Correct answer is option 'C'. Can you explain this answer?
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Most Upvoted Answer
A short bar magnet placed in a horizontal plane has its axis aligned a...
To find the total magnetic field on the normal bisector of the magnet at the same distance as the null point, we need to consider the contributions from both the magnet and the Earth's magnetic field.
1. Magnetic Field due to the Magnet:
The null points on the axis of the magnet indicate that the field due to the magnet is equal and opposite to the horizontal component of the Earth's magnetic field. Therefore, the horizontal component of the magnet's field at the null point is equal to the Earth's magnetic field.
Given that the null point is at a distance of 14 cm from the center of the magnet, we can use the formula for the magnetic field along the axis of a short bar magnet:
B = (μ₀/4π) * (2M/(d³))
Where:
B is the magnetic field
μ₀ is the permeability of free space (4π x 10^-7 Tm/A)
M is the magnetic moment of the magnet
d is the distance from the center of the magnet
Since the null point is at 14 cm from the center, the distance from the center to the null point is 7 cm (0.07 m). The magnetic field due to the magnet at this point is equal to the Earth's magnetic field, which is given as 0.36 G (1 G = 10^-4 T).
2. Total Magnetic Field:
The total magnetic field on the normal bisector at the same distance from the center of the magnet can be found by vector addition of the Earth's magnetic field and the magnetic field due to the magnet.
Since the angle of dip is zero, the Earth's magnetic field is entirely horizontal. Therefore, the total magnetic field will be the vector sum of the Earth's magnetic field and the magnetic field due to the magnet.
The total magnetic field is given by:
B_total = √(B_magnet² + B_earth² + 2B_magnetB_earthcosθ)
Where:
B_magnet is the magnetic field due to the magnet
B_earth is the Earth's magnetic field
θ is the angle between the two fields (which is 180° since they are opposite in direction)
Plugging in the values:
B_total = √((0.36 G)² + (0.36 G)² + 2(0.36 G)(0.36 G)cos180°)
B_total = √(0.1296 G² + 0.1296 G² - 2(0.1296 G²))
B_total = √(0.2592 G² - 0.2592 G²)
B_total = √0 G²
B_total = 0 G
Therefore, the total magnetic field on the normal bisector of the magnet at the same distance as the null point is 0 G. None of the given options (a, b, c, d) match the correct answer.
1. Magnetic Field due to the Magnet:
The null points on the axis of the magnet indicate that the field due to the magnet is equal and opposite to the horizontal component of the Earth's magnetic field. Therefore, the horizontal component of the magnet's field at the null point is equal to the Earth's magnetic field.
Given that the null point is at a distance of 14 cm from the center of the magnet, we can use the formula for the magnetic field along the axis of a short bar magnet:
B = (μ₀/4π) * (2M/(d³))
Where:
B is the magnetic field
μ₀ is the permeability of free space (4π x 10^-7 Tm/A)
M is the magnetic moment of the magnet
d is the distance from the center of the magnet
Since the null point is at 14 cm from the center, the distance from the center to the null point is 7 cm (0.07 m). The magnetic field due to the magnet at this point is equal to the Earth's magnetic field, which is given as 0.36 G (1 G = 10^-4 T).
2. Total Magnetic Field:
The total magnetic field on the normal bisector at the same distance from the center of the magnet can be found by vector addition of the Earth's magnetic field and the magnetic field due to the magnet.
Since the angle of dip is zero, the Earth's magnetic field is entirely horizontal. Therefore, the total magnetic field will be the vector sum of the Earth's magnetic field and the magnetic field due to the magnet.
The total magnetic field is given by:
B_total = √(B_magnet² + B_earth² + 2B_magnetB_earthcosθ)
Where:
B_magnet is the magnetic field due to the magnet
B_earth is the Earth's magnetic field
θ is the angle between the two fields (which is 180° since they are opposite in direction)
Plugging in the values:
B_total = √((0.36 G)² + (0.36 G)² + 2(0.36 G)(0.36 G)cos180°)
B_total = √(0.1296 G² + 0.1296 G² - 2(0.1296 G²))
B_total = √(0.2592 G² - 0.2592 G²)
B_total = √0 G²
B_total = 0 G
Therefore, the total magnetic field on the normal bisector of the magnet at the same distance as the null point is 0 G. None of the given options (a, b, c, d) match the correct answer.
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Community Answer
A short bar magnet placed in a horizontal plane has its axis aligned a...
At null point (and along the axis), earth's magnetic field and bar's magnetic field are opposite in direction.
On the equatorial line, the bar's magnetic field is opposite in direction to its field on the axis. Hence, on the equatorial line, the two fields add up.
As the null points are on the axis of the bar magnet, therefore,
B1= (μ0/4π)(2M/d3)=H
On the equatorial line of magnet at same distance(d), field due to the magnet is
B2= (μ0/4π)(M/d3)=B1/2=H/2
Therefore, total magnetic field at this point on equatorial line is
B=B2+H=3H/2=3×0.36G/2=0.54G
On the equatorial line, the bar's magnetic field is opposite in direction to its field on the axis. Hence, on the equatorial line, the two fields add up.
As the null points are on the axis of the bar magnet, therefore,
B1= (μ0/4π)(2M/d3)=H
On the equatorial line of magnet at same distance(d), field due to the magnet is
B2= (μ0/4π)(M/d3)=B1/2=H/2
Therefore, total magnetic field at this point on equatorial line is
B=B2+H=3H/2=3×0.36G/2=0.54G
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A short bar magnet placed in a horizontal plane has its axis aligned along the magnetic north-south direction. Null points are found on the axis of the magnet at 14 cm from the centre of the magnet. The earth’s magnetic field at the place is 0.36 G and the angle of dip is zero. What is the total magnetic field on the normal bisector of the magnet at the same distance as the null–point (i.e., 14 cm) from the centre of the magnet? (At null points, field due to a magnet is equal and opposite to the horizontal component of earth’s magnetic field.)a)0.64 G in the direction of earth’s field.b)0.62 G in the direction of earth’s field.c)0.54 G in the direction of earth’s field.d)0.58 G in the direction of earth’s field.Correct answer is option 'C'. Can you explain this answer?
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A short bar magnet placed in a horizontal plane has its axis aligned along the magnetic north-south direction. Null points are found on the axis of the magnet at 14 cm from the centre of the magnet. The earth’s magnetic field at the place is 0.36 G and the angle of dip is zero. What is the total magnetic field on the normal bisector of the magnet at the same distance as the null–point (i.e., 14 cm) from the centre of the magnet? (At null points, field due to a magnet is equal and opposite to the horizontal component of earth’s magnetic field.)a)0.64 G in the direction of earth’s field.b)0.62 G in the direction of earth’s field.c)0.54 G in the direction of earth’s field.d)0.58 G in the direction of earth’s field.Correct answer is option 'C'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about A short bar magnet placed in a horizontal plane has its axis aligned along the magnetic north-south direction. Null points are found on the axis of the magnet at 14 cm from the centre of the magnet. The earth’s magnetic field at the place is 0.36 G and the angle of dip is zero. What is the total magnetic field on the normal bisector of the magnet at the same distance as the null–point (i.e., 14 cm) from the centre of the magnet? (At null points, field due to a magnet is equal and opposite to the horizontal component of earth’s magnetic field.)a)0.64 G in the direction of earth’s field.b)0.62 G in the direction of earth’s field.c)0.54 G in the direction of earth’s field.d)0.58 G in the direction of earth’s field.Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A short bar magnet placed in a horizontal plane has its axis aligned along the magnetic north-south direction. Null points are found on the axis of the magnet at 14 cm from the centre of the magnet. The earth’s magnetic field at the place is 0.36 G and the angle of dip is zero. What is the total magnetic field on the normal bisector of the magnet at the same distance as the null–point (i.e., 14 cm) from the centre of the magnet? (At null points, field due to a magnet is equal and opposite to the horizontal component of earth’s magnetic field.)a)0.64 G in the direction of earth’s field.b)0.62 G in the direction of earth’s field.c)0.54 G in the direction of earth’s field.d)0.58 G in the direction of earth’s field.Correct answer is option 'C'. Can you explain this answer?.
A short bar magnet placed in a horizontal plane has its axis aligned along the magnetic north-south direction. Null points are found on the axis of the magnet at 14 cm from the centre of the magnet. The earth’s magnetic field at the place is 0.36 G and the angle of dip is zero. What is the total magnetic field on the normal bisector of the magnet at the same distance as the null–point (i.e., 14 cm) from the centre of the magnet? (At null points, field due to a magnet is equal and opposite to the horizontal component of earth’s magnetic field.)a)0.64 G in the direction of earth’s field.b)0.62 G in the direction of earth’s field.c)0.54 G in the direction of earth’s field.d)0.58 G in the direction of earth’s field.Correct answer is option 'C'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about A short bar magnet placed in a horizontal plane has its axis aligned along the magnetic north-south direction. Null points are found on the axis of the magnet at 14 cm from the centre of the magnet. The earth’s magnetic field at the place is 0.36 G and the angle of dip is zero. What is the total magnetic field on the normal bisector of the magnet at the same distance as the null–point (i.e., 14 cm) from the centre of the magnet? (At null points, field due to a magnet is equal and opposite to the horizontal component of earth’s magnetic field.)a)0.64 G in the direction of earth’s field.b)0.62 G in the direction of earth’s field.c)0.54 G in the direction of earth’s field.d)0.58 G in the direction of earth’s field.Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A short bar magnet placed in a horizontal plane has its axis aligned along the magnetic north-south direction. Null points are found on the axis of the magnet at 14 cm from the centre of the magnet. The earth’s magnetic field at the place is 0.36 G and the angle of dip is zero. What is the total magnetic field on the normal bisector of the magnet at the same distance as the null–point (i.e., 14 cm) from the centre of the magnet? (At null points, field due to a magnet is equal and opposite to the horizontal component of earth’s magnetic field.)a)0.64 G in the direction of earth’s field.b)0.62 G in the direction of earth’s field.c)0.54 G in the direction of earth’s field.d)0.58 G in the direction of earth’s field.Correct answer is option 'C'. Can you explain this answer?.
Solutions for A short bar magnet placed in a horizontal plane has its axis aligned along the magnetic north-south direction. Null points are found on the axis of the magnet at 14 cm from the centre of the magnet. The earth’s magnetic field at the place is 0.36 G and the angle of dip is zero. What is the total magnetic field on the normal bisector of the magnet at the same distance as the null–point (i.e., 14 cm) from the centre of the magnet? (At null points, field due to a magnet is equal and opposite to the horizontal component of earth’s magnetic field.)a)0.64 G in the direction of earth’s field.b)0.62 G in the direction of earth’s field.c)0.54 G in the direction of earth’s field.d)0.58 G in the direction of earth’s field.Correct answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12.
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Here you can find the meaning of A short bar magnet placed in a horizontal plane has its axis aligned along the magnetic north-south direction. Null points are found on the axis of the magnet at 14 cm from the centre of the magnet. The earth’s magnetic field at the place is 0.36 G and the angle of dip is zero. What is the total magnetic field on the normal bisector of the magnet at the same distance as the null–point (i.e., 14 cm) from the centre of the magnet? (At null points, field due to a magnet is equal and opposite to the horizontal component of earth’s magnetic field.)a)0.64 G in the direction of earth’s field.b)0.62 G in the direction of earth’s field.c)0.54 G in the direction of earth’s field.d)0.58 G in the direction of earth’s field.Correct answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
A short bar magnet placed in a horizontal plane has its axis aligned along the magnetic north-south direction. Null points are found on the axis of the magnet at 14 cm from the centre of the magnet. The earth’s magnetic field at the place is 0.36 G and the angle of dip is zero. What is the total magnetic field on the normal bisector of the magnet at the same distance as the null–point (i.e., 14 cm) from the centre of the magnet? (At null points, field due to a magnet is equal and opposite to the horizontal component of earth’s magnetic field.)a)0.64 G in the direction of earth’s field.b)0.62 G in the direction of earth’s field.c)0.54 G in the direction of earth’s field.d)0.58 G in the direction of earth’s field.Correct answer is option 'C'. Can you explain this answer?, a detailed solution for A short bar magnet placed in a horizontal plane has its axis aligned along the magnetic north-south direction. Null points are found on the axis of the magnet at 14 cm from the centre of the magnet. The earth’s magnetic field at the place is 0.36 G and the angle of dip is zero. What is the total magnetic field on the normal bisector of the magnet at the same distance as the null–point (i.e., 14 cm) from the centre of the magnet? (At null points, field due to a magnet is equal and opposite to the horizontal component of earth’s magnetic field.)a)0.64 G in the direction of earth’s field.b)0.62 G in the direction of earth’s field.c)0.54 G in the direction of earth’s field.d)0.58 G in the direction of earth’s field.Correct answer is option 'C'. Can you explain this answer? has been provided alongside types of A short bar magnet placed in a horizontal plane has its axis aligned along the magnetic north-south direction. Null points are found on the axis of the magnet at 14 cm from the centre of the magnet. The earth’s magnetic field at the place is 0.36 G and the angle of dip is zero. What is the total magnetic field on the normal bisector of the magnet at the same distance as the null–point (i.e., 14 cm) from the centre of the magnet? (At null points, field due to a magnet is equal and opposite to the horizontal component of earth’s magnetic field.)a)0.64 G in the direction of earth’s field.b)0.62 G in the direction of earth’s field.c)0.54 G in the direction of earth’s field.d)0.58 G in the direction of earth’s field.Correct answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A short bar magnet placed in a horizontal plane has its axis aligned along the magnetic north-south direction. Null points are found on the axis of the magnet at 14 cm from the centre of the magnet. The earth’s magnetic field at the place is 0.36 G and the angle of dip is zero. What is the total magnetic field on the normal bisector of the magnet at the same distance as the null–point (i.e., 14 cm) from the centre of the magnet? (At null points, field due to a magnet is equal and opposite to the horizontal component of earth’s magnetic field.)a)0.64 G in the direction of earth’s field.b)0.62 G in the direction of earth’s field.c)0.54 G in the direction of earth’s field.d)0.58 G in the direction of earth’s field.Correct answer is option 'C'. Can you explain this answer? tests, examples and also practice Class 12 tests.
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