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A short bar magnet of magnetic moment 5.25×10−2JT−1 is placed with its axis perpendicular to the earth’s field direction. At what distance from the centre of the magnet, the resultant field is inclined at 45 with earth’s field on its normal bisector . Magnitude of the earth’s field at the place is given to be 0.42 G. Ignore the length of the magnet in comparison to the distances involved.
  • a)
    5.5 cm
  • b)
    7.0 cm
  • c)
    6.0 cm
  • d)
    5 cm
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
A short bar magnet of magnetic moment5.25×10−2JT−1is...
According to the question, the resultant field is inclined at 45o with earth's magnetic field.
tanθ=BH​​/B
θ=45o
tanθ=1=BH​​/B
BH​=B= μo​M​/4πr3
Given, B= 0.42×10−4T
M=5.25×10−2J/T
Therefore,0.42+10−4=10−7×[(5.25×10−2)/r3]​
r3=12.5×10−5=125×10−6
r=5×10−2m = 5 cm
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Community Answer
A short bar magnet of magnetic moment5.25×10−2JT−1is...
1) B2= μM/4πR1^3=Be (for Be as they be at 45 angle)
4π10^-3 ×5.25×10^-2/4π×R1^3=0.42×10^-4

R1^3 =12.5 × 10^-5
R1 =5cm


2)at an axial plane
B2 = μ×2M/4πR2³
R2=5cm × 2^⅓
R2= 6.2cm (so this question can have two answer)
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A short bar magnet of magnetic moment5.25×10−2JT−1is placed with its axis perpendicular to the earth’s field direction. At what distance from the centre of the magnet, the resultant field is inclined at45with earth’s field on its normal bisector . Magnitude of the earth’s field at the place is given to be 0.42 G. Ignore the length of the magnet in comparison to the distances involved.a)5.5 cmb)7.0 cmc)6.0 cmd)5 cmCorrect answer is option 'D'. Can you explain this answer?
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A short bar magnet of magnetic moment5.25×10−2JT−1is placed with its axis perpendicular to the earth’s field direction. At what distance from the centre of the magnet, the resultant field is inclined at45with earth’s field on its normal bisector . Magnitude of the earth’s field at the place is given to be 0.42 G. Ignore the length of the magnet in comparison to the distances involved.a)5.5 cmb)7.0 cmc)6.0 cmd)5 cmCorrect answer is option 'D'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about A short bar magnet of magnetic moment5.25×10−2JT−1is placed with its axis perpendicular to the earth’s field direction. At what distance from the centre of the magnet, the resultant field is inclined at45with earth’s field on its normal bisector . Magnitude of the earth’s field at the place is given to be 0.42 G. Ignore the length of the magnet in comparison to the distances involved.a)5.5 cmb)7.0 cmc)6.0 cmd)5 cmCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A short bar magnet of magnetic moment5.25×10−2JT−1is placed with its axis perpendicular to the earth’s field direction. At what distance from the centre of the magnet, the resultant field is inclined at45with earth’s field on its normal bisector . Magnitude of the earth’s field at the place is given to be 0.42 G. Ignore the length of the magnet in comparison to the distances involved.a)5.5 cmb)7.0 cmc)6.0 cmd)5 cmCorrect answer is option 'D'. Can you explain this answer?.
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