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An aqueous solution of a solute AB has boiling point of 101.08° C and freezes at -1 .80 °C . AB is found to be 100% ionised at boiling point. If Kb/Kf = 0.3, then ABa)is 100% ionised at the freezing point of solutionb)behaves as non-electrolyte at the freezing point of solutionc)forms dimer at the freezing point of solutiond)forms trimer at the freezing point of solutionCorrect answer is option 'B'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared
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the Class 12 exam syllabus. Information about An aqueous solution of a solute AB has boiling point of 101.08° C and freezes at -1 .80 °C . AB is found to be 100% ionised at boiling point. If Kb/Kf = 0.3, then ABa)is 100% ionised at the freezing point of solutionb)behaves as non-electrolyte at the freezing point of solutionc)forms dimer at the freezing point of solutiond)forms trimer at the freezing point of solutionCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam.
Find important definitions, questions, meanings, examples, exercises and tests below for An aqueous solution of a solute AB has boiling point of 101.08° C and freezes at -1 .80 °C . AB is found to be 100% ionised at boiling point. If Kb/Kf = 0.3, then ABa)is 100% ionised at the freezing point of solutionb)behaves as non-electrolyte at the freezing point of solutionc)forms dimer at the freezing point of solutiond)forms trimer at the freezing point of solutionCorrect answer is option 'B'. Can you explain this answer?.
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Here you can find the meaning of An aqueous solution of a solute AB has boiling point of 101.08° C and freezes at -1 .80 °C . AB is found to be 100% ionised at boiling point. If Kb/Kf = 0.3, then ABa)is 100% ionised at the freezing point of solutionb)behaves as non-electrolyte at the freezing point of solutionc)forms dimer at the freezing point of solutiond)forms trimer at the freezing point of solutionCorrect answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
An aqueous solution of a solute AB has boiling point of 101.08° C and freezes at -1 .80 °C . AB is found to be 100% ionised at boiling point. If Kb/Kf = 0.3, then ABa)is 100% ionised at the freezing point of solutionb)behaves as non-electrolyte at the freezing point of solutionc)forms dimer at the freezing point of solutiond)forms trimer at the freezing point of solutionCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for An aqueous solution of a solute AB has boiling point of 101.08° C and freezes at -1 .80 °C . AB is found to be 100% ionised at boiling point. If Kb/Kf = 0.3, then ABa)is 100% ionised at the freezing point of solutionb)behaves as non-electrolyte at the freezing point of solutionc)forms dimer at the freezing point of solutiond)forms trimer at the freezing point of solutionCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of An aqueous solution of a solute AB has boiling point of 101.08° C and freezes at -1 .80 °C . AB is found to be 100% ionised at boiling point. If Kb/Kf = 0.3, then ABa)is 100% ionised at the freezing point of solutionb)behaves as non-electrolyte at the freezing point of solutionc)forms dimer at the freezing point of solutiond)forms trimer at the freezing point of solutionCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice An aqueous solution of a solute AB has boiling point of 101.08° C and freezes at -1 .80 °C . AB is found to be 100% ionised at boiling point. If Kb/Kf = 0.3, then ABa)is 100% ionised at the freezing point of solutionb)behaves as non-electrolyte at the freezing point of solutionc)forms dimer at the freezing point of solutiond)forms trimer at the freezing point of solutionCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice Class 12 tests.