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Ratio of Cp and Cv of a gas ‘X’ is 1.4. The number of atoms of the gas ‘X’ present in 11.2 litres of it at NTP will be [1989]
  • a)
    6.02 ×1023
  • b)
    1.2 × 1023
  • c)
    3.01 × 1023
  • d)
    2.01 × 1023
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
Ratio of Cp and Cv of a gas ‘X’ is 1.4. The number of atom...
Cp / Cv = 1.4 shows that the gas is diatomic. 22.4 litre at NTP ≡ 6.02 × 1023 molecules 11.2 L at NTP = 3.01 × 1023 molecules
= 3.01 × 1023 × 2 atoms = 6.02 × 1023 atoms
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Ratio of Cp and Cv of a gas ‘X’ is 1.4. The number of atom...
The ratio of Cp (specific heat at constant pressure) and Cv (specific heat at constant volume) of a gas depends on the degree of freedom of the gas molecules. For a monatomic gas (such as helium, neon, and argon), the ratio is:

Cp/Cv = 5/3

For a diatomic gas (such as nitrogen, oxygen, and hydrogen), the ratio is:

Cp/Cv = 7/5

This is because diatomic gases have two rotational degrees of freedom in addition to the three translational degrees of freedom, which affects their specific heat ratio.
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Ratio of Cp and Cv of a gas ‘X’ is 1.4. The number of atoms of the gas ‘X’ present in 11.2 litres of it at NTP will be [1989]a)6.02 ×1023b)1.2 × 1023c)3.01 × 1023d)2.01 × 1023Correct answer is option 'A'. Can you explain this answer? for Class 11 2025 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Ratio of Cp and Cv of a gas ‘X’ is 1.4. The number of atoms of the gas ‘X’ present in 11.2 litres of it at NTP will be [1989]a)6.02 ×1023b)1.2 × 1023c)3.01 × 1023d)2.01 × 1023Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 11 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Ratio of Cp and Cv of a gas ‘X’ is 1.4. The number of atoms of the gas ‘X’ present in 11.2 litres of it at NTP will be [1989]a)6.02 ×1023b)1.2 × 1023c)3.01 × 1023d)2.01 × 1023Correct answer is option 'A'. Can you explain this answer?.
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