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 A circle S passes through the point (0, 1) and is orthogonal to the circles (x – 1)2 + y2 = 16 and x2 + y2 = 1. Then (JEE Adv. 2014)
  • a)
    radius of S is 8
  • b)
    radius of S is 7
  • c)
    centre of S is (– 7, 1)
  • d)
    centre of S is (– 8, 1)
Correct answer is option 'B,C'. Can you explain this answer?
Verified Answer
A circle S passes through the point (0, 1) and is orthogonal to the ci...
Let the equation of circle be x2 + y2 + 2gx + 2 f y + c = 0
It passes through (0, 1)
∴ 1 + 2f + c = 0 ...(i)
This circle is orthogonal to (x – 1)2 + y2 = 16
i.e. x2 + y2 – 2x – 15 = 0 and x2 + y2 – 1 = 0
∴ We should have 2g (– 1) + 2f (0) = c – 15 or 2g + c – 15 = 0 ...(ii)
and 2g(0) + 2f (0) = c – 1 or c = 1 ...(iii)
Solving (i), (ii) and (iii), we get c = 1, g  = 7, f = – 1
∴ Required circle is x2 + y2 + 14x – 2y + 1 = 0
With centre (– 7, 1) and radius = 7
∴ (b) and (c) are correct options.
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A circle S passes through the point (0, 1) and is orthogonal to the circles (x – 1)2 + y2 = 16 and x2 + y2 = 1. Then (JEE Adv. 2014)a)radius of S is 8b)radius of S is 7c)centre of S is (– 7, 1)d)centre of S is (– 8, 1)Correct answer is option 'B,C'. Can you explain this answer?
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A circle S passes through the point (0, 1) and is orthogonal to the circles (x – 1)2 + y2 = 16 and x2 + y2 = 1. Then (JEE Adv. 2014)a)radius of S is 8b)radius of S is 7c)centre of S is (– 7, 1)d)centre of S is (– 8, 1)Correct answer is option 'B,C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A circle S passes through the point (0, 1) and is orthogonal to the circles (x – 1)2 + y2 = 16 and x2 + y2 = 1. Then (JEE Adv. 2014)a)radius of S is 8b)radius of S is 7c)centre of S is (– 7, 1)d)centre of S is (– 8, 1)Correct answer is option 'B,C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A circle S passes through the point (0, 1) and is orthogonal to the circles (x – 1)2 + y2 = 16 and x2 + y2 = 1. Then (JEE Adv. 2014)a)radius of S is 8b)radius of S is 7c)centre of S is (– 7, 1)d)centre of S is (– 8, 1)Correct answer is option 'B,C'. Can you explain this answer?.
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