JEE Exam  >  JEE Questions  >  Cucl2 solution is electrolysed using inert el... Start Learning for Free
Cucl2 solution is electrolysed using inert electrode if 11.2 ml cl2 is evolved at STP then find how much CU is deposited at cathode also find how many ampere current is passed through solution of 965 sec. given current efficiency is 20%?
Most Upvoted Answer
Cucl2 solution is electrolysed using inert electrode if 11.2 ml cl2 is...
Solution:

Electrolysis of CuCl2 solution using an inert electrode results in the deposition of Cu at the cathode and the evolution of Cl2 gas at the anode.

Finding the Amount of Cu Deposited

The balanced chemical equation for the electrolysis of CuCl2 is as follows:

CuCl2 (aq) → Cu (s) + Cl2 (g)

From the equation, it can be seen that for every mole of Cl2 gas evolved, one mole of Cu is deposited.

The volume of Cl2 gas evolved is given as 11.2 mL at STP. We can use the ideal gas law to convert this volume into moles:

PV = nRT

where P = 1 atm, V = 11.2 mL = 0.0112 L, n = ?, R = 0.08206 L atm mol-1 K-1, and T = 273 K.

Solving for n, we get:

n = PV/RT = (1 atm)(0.0112 L)/(0.08206 L atm mol-1 K-1)(273 K) = 0.000475 mol

Therefore, 0.000475 mol of Cu is deposited at the cathode.

Finding the Current Passed

The amount of charge (Q) passed through the solution can be calculated using Faraday's laws of electrolysis:

Q = nF

where n is the number of moles of electrons transferred during the electrolysis and F is the Faraday constant (96,485 C mol-1).

In the case of CuCl2, each mole of Cu requires two moles of electrons to be deposited at the cathode, so n = 2(0.000475) = 0.00095 mol.

Substituting into the equation for Q, we get:

Q = nF = (0.00095 mol)(96,485 C mol-1) = 91.6 C

The time taken for the electrolysis is given as 965 seconds, so the current (I) passed through the solution can be calculated using the equation:

I = Q/t

where t is the time taken for the electrolysis in seconds.

Substituting the given values, we get:

I = Q/t = (91.6 C)/(965 s) = 0.095 A

Finding the Current Efficiency

The current efficiency (CE) of the electrolysis is the ratio of the actual amount of metal deposited to the theoretical amount of metal that should have been deposited based on the amount of charge passed through the solution.

CE = (actual amount of metal deposited/theoretical amount of metal deposited) x 100%

The theoretical amount of Cu that should have been deposited can be calculated using the equation:

m = nM

where m is the mass of Cu deposited, n is the number of moles of Cu deposited, and M is the molar mass of Cu (63.55 g/mol).

Substituting the given values, we get:

m = nM = (0.000475 mol)(63.55 g/mol) = 0.0302 g

Therefore, the theoretical amount of Cu that should have been deposited is 0.0302 g.

The actual amount of Cu deposited is given as the same value, so the CE can be calculated as follows:

CE = (actual amount of metal deposited/theoretical amount of metal deposited)
Explore Courses for JEE exam

Similar JEE Doubts

A fuel cell is a cell that is continuously supplied with an oxidant and a reductant so that it can deliver a current indefinitely.Fuel cells offer the possibility of achieving high thermodynamic efficiency in the conversion of Gibbs energy into mechanical work. Internal combustion engines at best convert only the fraction (T2 T1)/T2 of the heat of combustion into mechanical work.While the thermodynamic efficiency of the fuel cell is given by, is theGibbs energy change for the cell reaction and H is the enthalpy change of the cell reaction.A hydrogen-oxygen fuel cell may have an acidic or alkaline electrolyte.Pt|H2(g)|H+(aq.)||H2O( l )|O2(g)|Pt; The above fuel cell is used to produce constant current supply under constant temperature 30 atm constant total pressure condition in a cylinder. If 10 moles H2 and 5 moles of O2 were taken initially. Rate of combustion of O2 is 10 milli moles per minute. The half cell reactions areTo maximize the power per unit mass of an electrochemical cell, the electronic and electrolytic resistances of the cell must be minimized. Since fused salts have lower electrolytic resistances than aqueous solutions, high-temperature electrochemical cells are of special interest for practical applications.Q.The above fuel cell is used completely as an electrolytic cell with Cu voltameter of resistance 26.94 W using Pt electrodes. Initially Cu voltameter contains 1 litre solution of 0.05M CuSO4.[H+] in solution after electrolysis (Assuming no change on volume of solution).

Cucl2 solution is electrolysed using inert electrode if 11.2 ml cl2 is evolved at STP then find how much CU is deposited at cathode also find how many ampere current is passed through solution of 965 sec. given current efficiency is 20%?
Question Description
Cucl2 solution is electrolysed using inert electrode if 11.2 ml cl2 is evolved at STP then find how much CU is deposited at cathode also find how many ampere current is passed through solution of 965 sec. given current efficiency is 20%? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Cucl2 solution is electrolysed using inert electrode if 11.2 ml cl2 is evolved at STP then find how much CU is deposited at cathode also find how many ampere current is passed through solution of 965 sec. given current efficiency is 20%? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Cucl2 solution is electrolysed using inert electrode if 11.2 ml cl2 is evolved at STP then find how much CU is deposited at cathode also find how many ampere current is passed through solution of 965 sec. given current efficiency is 20%?.
Solutions for Cucl2 solution is electrolysed using inert electrode if 11.2 ml cl2 is evolved at STP then find how much CU is deposited at cathode also find how many ampere current is passed through solution of 965 sec. given current efficiency is 20%? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of Cucl2 solution is electrolysed using inert electrode if 11.2 ml cl2 is evolved at STP then find how much CU is deposited at cathode also find how many ampere current is passed through solution of 965 sec. given current efficiency is 20%? defined & explained in the simplest way possible. Besides giving the explanation of Cucl2 solution is electrolysed using inert electrode if 11.2 ml cl2 is evolved at STP then find how much CU is deposited at cathode also find how many ampere current is passed through solution of 965 sec. given current efficiency is 20%?, a detailed solution for Cucl2 solution is electrolysed using inert electrode if 11.2 ml cl2 is evolved at STP then find how much CU is deposited at cathode also find how many ampere current is passed through solution of 965 sec. given current efficiency is 20%? has been provided alongside types of Cucl2 solution is electrolysed using inert electrode if 11.2 ml cl2 is evolved at STP then find how much CU is deposited at cathode also find how many ampere current is passed through solution of 965 sec. given current efficiency is 20%? theory, EduRev gives you an ample number of questions to practice Cucl2 solution is electrolysed using inert electrode if 11.2 ml cl2 is evolved at STP then find how much CU is deposited at cathode also find how many ampere current is passed through solution of 965 sec. given current efficiency is 20%? tests, examples and also practice JEE tests.
Explore Courses for JEE exam

Top Courses for JEE

Explore Courses
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev