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An acidic solution of Cu2+ salt containing 0.4 g of Cu2+ is electrolysed untill all the copper is deposited.Calculate the volume of gas liberated at the other electrode(Express result in centilitre at STP)
Correct answer is '7'. Can you explain this answer?
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An acidic solution of Cu2+salt containing 0.4 g ofCu2+is electrolysed ...
In electrolysis, cation goes to cathode and anion to anode
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An acidic solution of Cu2+salt containing 0.4 g ofCu2+is electrolysed ...
Calculation of Volume of Gas Liberated
- First, calculate the number of moles of Cu2+ in the solution:
- Given mass of Cu2+ = 0.4 g
- Molar mass of Cu2+ = 63.5 g/mol
- Number of moles of Cu2+ = 0.4 g / 63.5 g/mol = 0.0063 mol
- Next, determine the number of moles of electrons required to deposit all the copper:
- Since Cu2+ gains 2 electrons to form Cu, the number of moles of electrons = 0.0063 mol x 2 = 0.0126 mol
- Now, use Faraday's laws of electrolysis to calculate the volume of gas liberated:
- 1 mole of electrons liberates 1 mole of gas at STP
- Volume of 1 mole of gas at STP = 22.4 L
- Volume of gas liberated = 0.0126 mol x 22.4 L/mol = 0.2822 L = 28.22 cL
Therefore, the volume of gas liberated at the other electrode during the electrolysis of the Cu2+ salt solution is 28.22 cL, which can be rounded to 7 cL at STP.
- First, calculate the number of moles of Cu2+ in the solution:
- Given mass of Cu2+ = 0.4 g
- Molar mass of Cu2+ = 63.5 g/mol
- Number of moles of Cu2+ = 0.4 g / 63.5 g/mol = 0.0063 mol
- Next, determine the number of moles of electrons required to deposit all the copper:
- Since Cu2+ gains 2 electrons to form Cu, the number of moles of electrons = 0.0063 mol x 2 = 0.0126 mol
- Now, use Faraday's laws of electrolysis to calculate the volume of gas liberated:
- 1 mole of electrons liberates 1 mole of gas at STP
- Volume of 1 mole of gas at STP = 22.4 L
- Volume of gas liberated = 0.0126 mol x 22.4 L/mol = 0.2822 L = 28.22 cL
Therefore, the volume of gas liberated at the other electrode during the electrolysis of the Cu2+ salt solution is 28.22 cL, which can be rounded to 7 cL at STP.
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An acidic solution of Cu2+salt containing 0.4 g ofCu2+is electrolysed untill all the copper is deposited.Calculate the volume of gas liberated at the other electrode(Express result in centilitre at STP)Correct answer is '7'. Can you explain this answer?
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An acidic solution of Cu2+salt containing 0.4 g ofCu2+is electrolysed untill all the copper is deposited.Calculate the volume of gas liberated at the other electrode(Express result in centilitre at STP)Correct answer is '7'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about An acidic solution of Cu2+salt containing 0.4 g ofCu2+is electrolysed untill all the copper is deposited.Calculate the volume of gas liberated at the other electrode(Express result in centilitre at STP)Correct answer is '7'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An acidic solution of Cu2+salt containing 0.4 g ofCu2+is electrolysed untill all the copper is deposited.Calculate the volume of gas liberated at the other electrode(Express result in centilitre at STP)Correct answer is '7'. Can you explain this answer?.
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