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When 12.0 g of carbon reacted with oxygen to form CO & CO 2 at 25º C & constant pressure, 75.0 kcal of heat was liberated and no carbon remained . Calculate the mass of oxygen which reacted. ∆Hfº (CO2 ) = − 95 kcal mol− 1 , ∆ Hfº(CO) = − 24kcal mol−? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about When 12.0 g of carbon reacted with oxygen to form CO & CO 2 at 25º C & constant pressure, 75.0 kcal of heat was liberated and no carbon remained . Calculate the mass of oxygen which reacted. ∆Hfº (CO2 ) = − 95 kcal mol− 1 , ∆ Hfº(CO) = − 24kcal mol−? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for When 12.0 g of carbon reacted with oxygen to form CO & CO 2 at 25º C & constant pressure, 75.0 kcal of heat was liberated and no carbon remained . Calculate the mass of oxygen which reacted. ∆Hfº (CO2 ) = − 95 kcal mol− 1 , ∆ Hfº(CO) = − 24kcal mol−?.

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