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If no re boring allowance is to be given, then thickness of cylinder wall is max pressure is 3.5N/mm², bore diameter=200mm and permissible tensile stress is 40N/mm².
- a)7mm
- b)8mm
- c)9mm
- d)10mm
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
If no re boring allowance is to be given, then thickness of cylinder w...
Explanation: t=pD/2σ=8.75mm.
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If no re boring allowance is to be given, then thickness of cylinder w...
Understanding the Problem
To determine the thickness of a cylinder wall under given conditions, we need to apply the principles of mechanical engineering related to stress and pressure.
Given Data
- Maximum pressure (P) = 3.5 N/mm²
- Bore diameter (d) = 200 mm
- Permissible tensile stress (σ) = 40 N/mm²
Formulas to Use
We will use the formula for the thickness of a thin-walled cylinder:
t = (P * d) / (2 * σ)
Where:
- t = wall thickness
- P = internal pressure
- d = diameter of the cylinder
- σ = permissible tensile stress
Calculating the Thickness
1. Convert Bore Diameter:
Diameter (d) = 200 mm = 0.2 m
2. Plug Values into the Formula:
- t = (3.5 N/mm² * 200 mm) / (2 * 40 N/mm²)
- t = (700 N/mm) / (80 N/mm²)
- t = 8.75 mm
3. Selecting the Closest Value:
Since no re-boring allowance is given, we round up to the nearest whole number. Thus, the thickness of the cylinder wall is approximately 9 mm.
Conclusion
The correct answer is option 'C', which states that the thickness of the cylinder wall should be 9 mm. This calculation ensures that the cylinder can safely withstand the internal pressure without exceeding the permissible tensile stress.
To determine the thickness of a cylinder wall under given conditions, we need to apply the principles of mechanical engineering related to stress and pressure.
Given Data
- Maximum pressure (P) = 3.5 N/mm²
- Bore diameter (d) = 200 mm
- Permissible tensile stress (σ) = 40 N/mm²
Formulas to Use
We will use the formula for the thickness of a thin-walled cylinder:
t = (P * d) / (2 * σ)
Where:
- t = wall thickness
- P = internal pressure
- d = diameter of the cylinder
- σ = permissible tensile stress
Calculating the Thickness
1. Convert Bore Diameter:
Diameter (d) = 200 mm = 0.2 m
2. Plug Values into the Formula:
- t = (3.5 N/mm² * 200 mm) / (2 * 40 N/mm²)
- t = (700 N/mm) / (80 N/mm²)
- t = 8.75 mm
3. Selecting the Closest Value:
Since no re-boring allowance is given, we round up to the nearest whole number. Thus, the thickness of the cylinder wall is approximately 9 mm.
Conclusion
The correct answer is option 'C', which states that the thickness of the cylinder wall should be 9 mm. This calculation ensures that the cylinder can safely withstand the internal pressure without exceeding the permissible tensile stress.
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If no re boring allowance is to be given, then thickness of cylinder wall is max pressure is 3.5N/mm², bore diameter=200mm and permissible tensile stress is 40N/mm².a)7mmb)8mmc)9mmd)10mmCorrect answer is option 'C'. Can you explain this answer?
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If no re boring allowance is to be given, then thickness of cylinder wall is max pressure is 3.5N/mm², bore diameter=200mm and permissible tensile stress is 40N/mm².a)7mmb)8mmc)9mmd)10mmCorrect answer is option 'C'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about If no re boring allowance is to be given, then thickness of cylinder wall is max pressure is 3.5N/mm², bore diameter=200mm and permissible tensile stress is 40N/mm².a)7mmb)8mmc)9mmd)10mmCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If no re boring allowance is to be given, then thickness of cylinder wall is max pressure is 3.5N/mm², bore diameter=200mm and permissible tensile stress is 40N/mm².a)7mmb)8mmc)9mmd)10mmCorrect answer is option 'C'. Can you explain this answer?.
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