Verification of a-(b-c) = (a-b) - c

To verify the given equation, we need to substitute the values of a, b, and c and simplify both sides of the equation to check if they are equal.

Given: a = 9, b = 6, c = 4

Left-hand side (LHS): a-(b-c)
Substituting the values of a, b, and c in the equation:
LHS = 9 - (6 - 4)

Now, let's simplify the expression inside the parentheses first:
LHS = 9 - (2)

Finally, perform the subtraction:
LHS = 7

Right-hand side (RHS): (a-b) - c
Substituting the values of a, b, and c in the equation:
RHS = (9 - 6) - 4

Perform the subtraction inside the parentheses first:
RHS = 3 - 4

Finally, perform the subtraction:
RHS = -1

Comparing LHS and RHS:
LHS = 7
RHS = -1

Since LHS ≠ RHS, it is clear that the equation a-(b-c) = (a-b) - c is not true for the given values of a = 9, b = 6, and c = 4.

Explanation:
The given equation represents the subtraction of integers. Subtraction is the operation of finding the difference between two numbers. In this equation, a, b, and c are variables representing integers.

To simplify the equation, we need to follow the order of operations, which requires us to perform the operations inside parentheses first, then perform the subtraction.

In the LHS, we subtract (b-c) first. Here, (b-c) evaluates to (6-4) which is equal to 2. So, the expression becomes a-2. Substituting the value of a as 9, we have 9-2 which equals 7.

In the RHS, we subtract (a-b) first. Here, (a-b) evaluates to (9-6) which is equal to 3. So, the expression becomes 3-c. Substituting the value of c as 4, we have 3-4 which equals -1.

Since 7 and -1 are not equal, we can conclude that the given equation is not true for the given values of a = 9, b = 6, and c = 4.

Therefore, the equation a-(b-c) = (a-b) - c is not verified for the given values.

=a-b-c=(a-b)-c
=9-(6-4)=9-6
9-2=3
7==\3
hence not verified