What is the least no by which 2800 should be multiplied so that the pr...
Solution:
To make 2800 a perfect square, we need to multiply it with a number such that the product is a perfect square. Let that number be x.
Prime factorization of 2800 = $2^3$ × $5^2$ × $7$
For the product to be a perfect square, each prime factor must have an even power.
Let the power of 2 be a, power of 5 be b, and power of 7 be c.
Therefore, x should be such that:
$2^a$ × $5^b$ × $7^c$ is a perfect square
Applying the condition for a perfect square, a, b, and c should be even.
The least value of x to make 2800 a perfect square is obtained by taking the smallest even powers of 2, 5, and 7.
Hence, the least value of x is 2 × 5 × 7 = 70.
Therefore, option (2) is correct.
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Solution:
To make 2800 a perfect square, we need to multiply it with a number such that the product is a perfect square. Let that number be x.
Prime factorization of 2800 = $2^3$ × $5^2$ × $7$
For the product to be a perfect square, each prime factor must have an even power.
Let the power of 2 be a, power of 5 be b, and power of 7 be c.
Therefore, x should be such that:
$2^a$ × $5^b$ × $7^c$ is a perfect square
Applying the condition for a perfect square, a, b, and c should be even.
The least value of x to make 2800 a perfect square is obtained by taking the smallest even powers of 2, 5, and 7.
Hence, the least value of x is 2 × 5 × 7 = 70.
Therefore, option (2) is correct.