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One of the base angle of of the isosceles triangle is twice the vertex angle.Find the angles of a triangle ?
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One of the base angle of of the isosceles triangle is twice the vertex...
Given information:
One of the base angles of the isosceles triangle is twice the vertex angle.

Let's find the angles of the triangle:
1. Let the vertex angle be x degrees.
2. Since one base angle is twice the vertex angle, the base angle will be 2x degrees.
3. Since the triangle is isosceles, the base angles are equal.
4. Therefore, the sum of all angles in a triangle is 180 degrees.

Now, let's calculate the angles:
- Vertex angle = x degrees
- Base angle = 2x degrees
- Base angle = 2x degrees

Using the sum of angles in a triangle:
x + 2x + 2x = 180
5x = 180
x = 36

Therefore, the angles of the triangle are:
- Vertex angle = 36 degrees
- Base angles = 2x = 72 degrees

Conclusion:
The angles of the triangle are 36 degrees, 72 degrees, and 72 degrees.
Community Answer
One of the base angle of of the isosceles triangle is twice the vertex...
Angle is 180
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One of the base angle of of the isosceles triangle is twice the vertex angle.Find the angles of a triangle ?
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