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The three liquids 1, 2, and 3 with vapor pressures V1, V2 and V3 respectively, are kept under same pressure. If V1 > V2 > V3, which liquid will start boiling early?
  • a)
    liquid 1
  • b)
    liquid 2
  • c)
    liquid 3
  • d)
    they will start boiling at the same time
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
The three liquids 1, 2, and 3 with vapor pressures V1, V2 and V3 respe...
Explanation: A liquid starts to boil whenever it’s absolute pressure drops below it’s vapor pressure. Thus, the absolute pressure of liquid 1 will drop early, as a result it’ll start boiling early.
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Most Upvoted Answer
The three liquids 1, 2, and 3 with vapor pressures V1, V2 and V3 respe...
Is greater than V2 and V2 is greater than V3, it means that liquid 1 has the highest tendency to evaporate and liquid 3 has the lowest tendency to evaporate.

Under the same pressure, the liquid with the highest vapor pressure will evaporate more quickly and have a higher concentration of vapor in the air above it. This means that the concentration of vapor above liquid 1 will be the highest, followed by liquid 2 and then liquid 3.

If the three liquids are mixed together, the resulting vapor pressure will be a combination of the individual vapor pressures of each liquid. The overall vapor pressure will be closer to the vapor pressure of the liquid with the highest tendency to evaporate (liquid 1) than the others.
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The three liquids 1, 2, and 3 with vapor pressures V1, V2 and V3 respectively, are kept under same pressure. If V1 > V2 > V3, which liquid will start boiling early?a)liquid 1b)liquid 2c)liquid 3d)they will start boiling at the same timeCorrect answer is option 'A'. Can you explain this answer?
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