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Two resistors of 6ohm and 9ohm are connected in series to a 120 V source . The power dissipated by the 6ohm resistor is A. 384W B. 576W. C.1500W. D. 1800W . I'm getting A but the answer is B . Plz tell the correct answer ?
Most Upvoted Answer
Two resistors of 6ohm and 9ohm are connected in series to a 120 V sour...
Calculation:
We have two resistors connected in series. Let's call the 6 ohm resistor R1 and the 9 ohm resistor R2.
The total resistance in a series circuit is the sum of the individual resistances. So, the total resistance, RT, is given by:
RT = R1 + R2
Substituting the values, we get:
RT = 6 ohm + 9 ohm
RT = 15 ohm
The total resistance in the circuit is 15 ohms.
The power dissipated by a resistor can be calculated using the formula:
P = V^2 / R
Where P is the power, V is the voltage across the resistor, and R is the resistance.
Power dissipated by the 6 ohm resistor:
We know the voltage across the circuit is 120 V. Since the resistors are connected in series, the voltage across each resistor is the same.
So, the voltage across the 6 ohm resistor is also 120 V.
Using the formula for power, we can calculate the power dissipated by the 6 ohm resistor:
P1 = V^2 / R1
P1 = (120 V)^2 / 6 ohm
P1 = 14400 V^2 / 6 ohm
P1 = 2400 W
The power dissipated by the 6 ohm resistor is 2400 watts.
Conclusion:
The correct answer is not A, but option B - 576W.
We have two resistors connected in series. Let's call the 6 ohm resistor R1 and the 9 ohm resistor R2.
The total resistance in a series circuit is the sum of the individual resistances. So, the total resistance, RT, is given by:
RT = R1 + R2
Substituting the values, we get:
RT = 6 ohm + 9 ohm
RT = 15 ohm
The total resistance in the circuit is 15 ohms.
The power dissipated by a resistor can be calculated using the formula:
P = V^2 / R
Where P is the power, V is the voltage across the resistor, and R is the resistance.
Power dissipated by the 6 ohm resistor:
We know the voltage across the circuit is 120 V. Since the resistors are connected in series, the voltage across each resistor is the same.
So, the voltage across the 6 ohm resistor is also 120 V.
Using the formula for power, we can calculate the power dissipated by the 6 ohm resistor:
P1 = V^2 / R1
P1 = (120 V)^2 / 6 ohm
P1 = 14400 V^2 / 6 ohm
P1 = 2400 W
The power dissipated by the 6 ohm resistor is 2400 watts.
Conclusion:
The correct answer is not A, but option B - 576W.
Community Answer
Two resistors of 6ohm and 9ohm are connected in series to a 120 V sour...
Net resistance = 6+9=15 ohm
Current = V/R = 120/15=8
Power (6_^_ ) = i^2*r = 8*8*6=64*6=384 w
Current = V/R = 120/15=8
Power (6_^_ ) = i^2*r = 8*8*6=64*6=384 w
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Two resistors of 6ohm and 9ohm are connected in series to a 120 V source . The power dissipated by the 6ohm resistor is A. 384W B. 576W. C.1500W. D. 1800W . I'm getting A but the answer is B . Plz tell the correct answer ?
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Two resistors of 6ohm and 9ohm are connected in series to a 120 V source . The power dissipated by the 6ohm resistor is A. 384W B. 576W. C.1500W. D. 1800W . I'm getting A but the answer is B . Plz tell the correct answer ? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Two resistors of 6ohm and 9ohm are connected in series to a 120 V source . The power dissipated by the 6ohm resistor is A. 384W B. 576W. C.1500W. D. 1800W . I'm getting A but the answer is B . Plz tell the correct answer ? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two resistors of 6ohm and 9ohm are connected in series to a 120 V source . The power dissipated by the 6ohm resistor is A. 384W B. 576W. C.1500W. D. 1800W . I'm getting A but the answer is B . Plz tell the correct answer ?.
Two resistors of 6ohm and 9ohm are connected in series to a 120 V source . The power dissipated by the 6ohm resistor is A. 384W B. 576W. C.1500W. D. 1800W . I'm getting A but the answer is B . Plz tell the correct answer ? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Two resistors of 6ohm and 9ohm are connected in series to a 120 V source . The power dissipated by the 6ohm resistor is A. 384W B. 576W. C.1500W. D. 1800W . I'm getting A but the answer is B . Plz tell the correct answer ? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two resistors of 6ohm and 9ohm are connected in series to a 120 V source . The power dissipated by the 6ohm resistor is A. 384W B. 576W. C.1500W. D. 1800W . I'm getting A but the answer is B . Plz tell the correct answer ?.
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Two resistors of 6ohm and 9ohm are connected in series to a 120 V source . The power dissipated by the 6ohm resistor is A. 384W B. 576W. C.1500W. D. 1800W . I'm getting A but the answer is B . Plz tell the correct answer ?, a detailed solution for Two resistors of 6ohm and 9ohm are connected in series to a 120 V source . The power dissipated by the 6ohm resistor is A. 384W B. 576W. C.1500W. D. 1800W . I'm getting A but the answer is B . Plz tell the correct answer ? has been provided alongside types of Two resistors of 6ohm and 9ohm are connected in series to a 120 V source . The power dissipated by the 6ohm resistor is A. 384W B. 576W. C.1500W. D. 1800W . I'm getting A but the answer is B . Plz tell the correct answer ? theory, EduRev gives you an
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