JEE Exam  >  JEE Questions  >  Degree of dissociation of 0.1 M HCN solution ... Start Learning for Free
Degree of dissociation of 0.1 M HCN solution is 0.01%. Its ionization constant would be?
Most Upvoted Answer
Degree of dissociation of 0.1 M HCN solution is 0.01%. Its ionization ...


Introduction:
The degree of dissociation is a measure of the extent to which a solute dissociates into ions in a solution. It is defined as the ratio of the number of moles of dissociated solute to the initial number of moles of the solute. In this case, we are given that the degree of dissociation of a 0.1 M HCN (hydrogen cyanide) solution is 0.01%.

Calculating the Degree of Dissociation:
To calculate the degree of dissociation, we can use the formula:
Degree of Dissociation (α) = (Number of moles of dissociated solute) / (Initial number of moles of solute)
Given that the concentration of the HCN solution is 0.1 M, we can assume that the initial number of moles of HCN is also 0.1 mol.

Using the given degree of dissociation of 0.01%, we can calculate the number of moles of dissociated solute by multiplying the initial number of moles by the degree of dissociation:
Number of moles of dissociated solute = 0.1 mol x (0.01 / 100) = 0.0001 mol

Therefore, the degree of dissociation of the 0.1 M HCN solution is 0.0001 mol.

Calculating the Ionization Constant:
The ionization constant, or the dissociation constant (Ka), is a measure of the strength of an acid or base in solution. It is defined as the ratio of the concentration of the products to the concentration of the reactants in a dissociation reaction.

In the case of HCN, the dissociation can be represented by the equation:
HCN ⇌ H+ + CN-

The ionization constant (Ka) is given by the equation:
Ka = [H+][CN-] / [HCN]

Given that the concentration of HCN is 0.1 M and the degree of dissociation is 0.01%, we can substitute these values into the equation to calculate the ionization constant.

The concentration of HCN that is dissociated is:
[HCN] dissociated = 0.0001 mol / 1 L = 0.0001 M

The concentration of H+ and CN- ions is equal to the concentration of dissociated HCN:
[H+] = [CN-] = 0.0001 M

Substituting these values into the equation for Ka:
Ka = (0.0001 M)(0.0001 M) / (0.1 M) = 0.00000001 / 0.1 = 0.0000001

Therefore, the ionization constant (Ka) for the 0.1 M HCN solution with a degree of dissociation of 0.01% is 0.0000001.

Conclusion:
In this case, we calculated the degree of dissociation of a 0.1 M HCN solution to be 0.0001 mol. Using this value, we calculated the ionization constant (Ka) to be 0.0000001. The ionization constant provides information about the strength of the acid in solution and can be used to determine the extent of dissociation.
Community Answer
Degree of dissociation of 0.1 M HCN solution is 0.01%. Its ionization ...
Use K=c (alpha^2) /1- alpha
Explore Courses for JEE exam

Similar JEE Doubts

Degree of dissociation of 0.1 M HCN solution is 0.01%. Its ionization constant would be?
Question Description
Degree of dissociation of 0.1 M HCN solution is 0.01%. Its ionization constant would be? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Degree of dissociation of 0.1 M HCN solution is 0.01%. Its ionization constant would be? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Degree of dissociation of 0.1 M HCN solution is 0.01%. Its ionization constant would be?.
Solutions for Degree of dissociation of 0.1 M HCN solution is 0.01%. Its ionization constant would be? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of Degree of dissociation of 0.1 M HCN solution is 0.01%. Its ionization constant would be? defined & explained in the simplest way possible. Besides giving the explanation of Degree of dissociation of 0.1 M HCN solution is 0.01%. Its ionization constant would be?, a detailed solution for Degree of dissociation of 0.1 M HCN solution is 0.01%. Its ionization constant would be? has been provided alongside types of Degree of dissociation of 0.1 M HCN solution is 0.01%. Its ionization constant would be? theory, EduRev gives you an ample number of questions to practice Degree of dissociation of 0.1 M HCN solution is 0.01%. Its ionization constant would be? tests, examples and also practice JEE tests.
Explore Courses for JEE exam

Top Courses for JEE

Explore Courses
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev