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For a cell, the terminal potential difference is 3.6 V, when the circuit is open. If the potential difference reduces to 3 V, when cell is connected to a resistance of 5 Ω, the internal resistance of cell is
  • a)
    1 Ω
  • b)
    2 Ω
  • c)
    4 Ω
  • d)
    8 Ω
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
For a cell, the terminal potential difference is 3.6 V, when the circu...
Given: Terminal potential difference, Vt = 3.6 V; Potential difference across the resistance, Vr = 3 V; Resistance, R = 5 Ω

To find: Internal resistance, r

Formula used: Vt = E - Ir, where E is the emf of the cell and I is the current flowing through the circuit

Solution:

1. When the circuit is open
- No current flows through the circuit
- Therefore, Vt = E (as there is no potential drop across internal resistance)
- Vt = 3.6 V (given)
- E = 3.6 V

2. When the cell is connected to the resistance of 5 Ω
- Current, I = Vr / R = 3 / 5 A
- Using the formula Vt = E - Ir, we get
- 3.6 = 3 + r * (3/5)
- r = (3.6 - 3) / (3/5)
- r = 1 Ω

Therefore, the internal resistance of the cell is 1 Ω.
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Community Answer
For a cell, the terminal potential difference is 3.6 V, when the circu...
First by question we consider V(effective)=3
then,. 3=i5. (1)
then we take internal resistance and add it to circuit. then , 3.6 = i(5+r). (2)
solving the two eq. we get r=1
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For a cell, the terminal potential difference is 3.6 V, when the circuit is open. If the potential difference reduces to 3 V, when cell is connected to a resistance of 5 Ω, the internal resistance of cell isa)1 Ωb)2 Ωc)4 Ωd)8 ΩCorrect answer is option 'A'. Can you explain this answer?
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