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The potential difference between the terminals of a cell in open circuit is 2.2 volt with resistance of 5 ohm across the terminals of a cell, the terminal potential difference is 1.8 volt. The internal resistance of the cell is
  • a)
    9/10 ohm
  • b)
    10/9ohm
  • c)
    7/12ohm
  • d)
    12/7ohm
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
The potential difference between the terminals of a cell in open circu...
Given Data:
- Potential difference in open circuit: 2.2 V
- Potential difference with 5 ohm resistance: 1.8 V

Calculating Internal Resistance:
- Let the internal resistance of the cell be denoted by 'r'
- Using the formula for potential difference across a resistor in a circuit:
V = EMF - Ir
Where,
V = potential difference across the resistor (1.8 V)
EMF = potential difference of the cell in open circuit (2.2 V)
I = current flowing through the circuit
- Since the resistance across the cell is 5 ohms, the current can be calculated as:
I = V/R = 1.8/5 = 0.36 A
- Substituting these values into the formula:
1.8 = 2.2 - 0.36r
0.36r = 2.2 - 1.8
0.36r = 0.4
r = 0.4/0.36 = 10/9 ohm
Therefore, the internal resistance of the cell is 10/9 ohm, which corresponds to option B.
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The potential difference between the terminals of a cell in open circuit is 2.2 volt with resistance of 5 ohm across the terminals of a cell, the terminal potential difference is 1.8 volt. The internal resistance of the cell isa)9/10 ohmb)10/9ohmc)7/12ohmd)12/7ohmCorrect answer is option 'B'. Can you explain this answer?
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