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In the circuit shown in figure, A and B are two cells of the same emf, E and of internal resistances rA and rB, respectively. L is an ideal inductor and C is an ideal capacitor. The key K is closed. When the current in the circuit becomes steady, what should be the value of R so that the potential difference across the terminals of cell A is zero?
  • a)
    R = rA – rB, if rA > rB
  • b)
  • c)
  • d)
    The potential difference between the terminals of cell A will be equal to zero for no value of R.
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
In the circuit shown in figure, A and B are two cells of the same emf...
When the key, K is inserted, the current starts growing and after some time it acquires a steady value. At this stage, no current flows through the capacitor (because an ideal capacitor offers an infinite resistance to a steady current). All the current flows through the inductor (because an ideal inductor offers zero resistance to a steady current). Now, the network of resistors is a balanced wheatstone bridge. Hence, no current flows through the resistance 2R. Therefore, this resistance can be ignored. The net resistance between points X and Y = resistance of the parallel combination of 2 R and 2 R = = R
Hence, the current in the circuit is
I =
Now, the terminal voltage of cell A is
2rA = R + rA + rB or R = rA – rB
So, the correct choice is (a).
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In the circuit shown in figure, A and B are two cells of the same emf, E and of internal resistances rA and rB, respectively. L is an ideal inductor and C is an ideal capacitor. The key K is closed. When the current in the circuit becomes steady, what should be the value of R so that the potential difference across the terminals of cell A is zero?a)R = rA – rB, if rA > rBb)c)d)The potential difference between the terminals of cell A will be equal to zero for no value of R.Correct answer is option 'A'. Can you explain this answer?
Question Description
In the circuit shown in figure, A and B are two cells of the same emf, E and of internal resistances rA and rB, respectively. L is an ideal inductor and C is an ideal capacitor. The key K is closed. When the current in the circuit becomes steady, what should be the value of R so that the potential difference across the terminals of cell A is zero?a)R = rA – rB, if rA > rBb)c)d)The potential difference between the terminals of cell A will be equal to zero for no value of R.Correct answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about In the circuit shown in figure, A and B are two cells of the same emf, E and of internal resistances rA and rB, respectively. L is an ideal inductor and C is an ideal capacitor. The key K is closed. When the current in the circuit becomes steady, what should be the value of R so that the potential difference across the terminals of cell A is zero?a)R = rA – rB, if rA > rBb)c)d)The potential difference between the terminals of cell A will be equal to zero for no value of R.Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In the circuit shown in figure, A and B are two cells of the same emf, E and of internal resistances rA and rB, respectively. L is an ideal inductor and C is an ideal capacitor. The key K is closed. When the current in the circuit becomes steady, what should be the value of R so that the potential difference across the terminals of cell A is zero?a)R = rA – rB, if rA > rBb)c)d)The potential difference between the terminals of cell A will be equal to zero for no value of R.Correct answer is option 'A'. Can you explain this answer?.
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