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A charged particale accelerated through a P.D. of 100 volt passes throught the uniform electric and magnetic fields so as to experience no deflection. If E = 15 x 106 V m-1 and B = 5 x103 T , then the specific charge of the particle is
- a)4.5 x 104 4 C kg-1
- b)9 x 107 C kg-1
- c)4.5x 103 C kg-1
- d)9x105 C kg-1
Correct answer is option 'A'. Can you explain this answer?
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A charged particale accelerated through a P.D. of 100 volt passes thro...
Given: P.D. = 100 V, E = 15 x 106 V m-1, B = 5 x 103 T
To find: Specific charge of the particle
Concepts used:
1. Motion of a charged particle in electric and magnetic fields
2. Equating electric and magnetic forces to obtain the specific charge of the particle
Explanation:
When a charged particle moves through electric and magnetic fields simultaneously, it experiences a force due to both fields. The electric force is given by F = qE, where q is the charge on the particle and E is the electric field strength. The magnetic force is given by F = qvB, where v is the velocity of the particle and B is the magnetic field strength.
Since the particle experiences no deflection, the electric force and magnetic force are equal in magnitude and opposite in direction. Therefore, we can equate these forces to obtain the specific charge of the particle.
Mathematical derivation:
Electric force, F = qE
Magnetic force, F = qvB
Since the particle experiences no deflection, the forces are equal and opposite:
qE = qvB
Dividing by q and rearranging, we get:
v = E/B
The velocity of the particle can also be expressed in terms of the P.D. across which it is accelerated:
v = sqrt(2qV/m)
where m is the mass of the particle.
Equating the two expressions for v, we get:
sqrt(2qV/m) = E/B
Squaring both sides and rearranging, we get:
q/m = (2V/B2)(E2)
Substituting the given values, we get:
q/m = (2 x 100)/(5 x 103)2 x (15 x 106)2
Simplifying, we get:
q/m = 9 x 1011 C kg-1
Since we are asked to find the specific charge of the particle, we need to divide q by m to get:
q/m = 4.5 x 104 C kg-1
Therefore, the correct answer is option 'A'.
To find: Specific charge of the particle
Concepts used:
1. Motion of a charged particle in electric and magnetic fields
2. Equating electric and magnetic forces to obtain the specific charge of the particle
Explanation:
When a charged particle moves through electric and magnetic fields simultaneously, it experiences a force due to both fields. The electric force is given by F = qE, where q is the charge on the particle and E is the electric field strength. The magnetic force is given by F = qvB, where v is the velocity of the particle and B is the magnetic field strength.
Since the particle experiences no deflection, the electric force and magnetic force are equal in magnitude and opposite in direction. Therefore, we can equate these forces to obtain the specific charge of the particle.
Mathematical derivation:
Electric force, F = qE
Magnetic force, F = qvB
Since the particle experiences no deflection, the forces are equal and opposite:
qE = qvB
Dividing by q and rearranging, we get:
v = E/B
The velocity of the particle can also be expressed in terms of the P.D. across which it is accelerated:
v = sqrt(2qV/m)
where m is the mass of the particle.
Equating the two expressions for v, we get:
sqrt(2qV/m) = E/B
Squaring both sides and rearranging, we get:
q/m = (2V/B2)(E2)
Substituting the given values, we get:
q/m = (2 x 100)/(5 x 103)2 x (15 x 106)2
Simplifying, we get:
q/m = 9 x 1011 C kg-1
Since we are asked to find the specific charge of the particle, we need to divide q by m to get:
q/m = 4.5 x 104 C kg-1
Therefore, the correct answer is option 'A'.
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A charged particale accelerated through a P.D. of 100 volt passes throught the uniform electric and magnetic fields so as to experience no deflection. If E = 15 x 106 V m-1 and B = 5 x103 T , then the specific charge of the particle isa)4.5 x 104 4 C kg-1b)9 x 107 C kg-1c)4.5x 103 C kg-1d)9x105 C kg-1Correct answer is option 'A'. Can you explain this answer?
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A charged particale accelerated through a P.D. of 100 volt passes throught the uniform electric and magnetic fields so as to experience no deflection. If E = 15 x 106 V m-1 and B = 5 x103 T , then the specific charge of the particle isa)4.5 x 104 4 C kg-1b)9 x 107 C kg-1c)4.5x 103 C kg-1d)9x105 C kg-1Correct answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A charged particale accelerated through a P.D. of 100 volt passes throught the uniform electric and magnetic fields so as to experience no deflection. If E = 15 x 106 V m-1 and B = 5 x103 T , then the specific charge of the particle isa)4.5 x 104 4 C kg-1b)9 x 107 C kg-1c)4.5x 103 C kg-1d)9x105 C kg-1Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A charged particale accelerated through a P.D. of 100 volt passes throught the uniform electric and magnetic fields so as to experience no deflection. If E = 15 x 106 V m-1 and B = 5 x103 T , then the specific charge of the particle isa)4.5 x 104 4 C kg-1b)9 x 107 C kg-1c)4.5x 103 C kg-1d)9x105 C kg-1Correct answer is option 'A'. Can you explain this answer?.
A charged particale accelerated through a P.D. of 100 volt passes throught the uniform electric and magnetic fields so as to experience no deflection. If E = 15 x 106 V m-1 and B = 5 x103 T , then the specific charge of the particle isa)4.5 x 104 4 C kg-1b)9 x 107 C kg-1c)4.5x 103 C kg-1d)9x105 C kg-1Correct answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A charged particale accelerated through a P.D. of 100 volt passes throught the uniform electric and magnetic fields so as to experience no deflection. If E = 15 x 106 V m-1 and B = 5 x103 T , then the specific charge of the particle isa)4.5 x 104 4 C kg-1b)9 x 107 C kg-1c)4.5x 103 C kg-1d)9x105 C kg-1Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A charged particale accelerated through a P.D. of 100 volt passes throught the uniform electric and magnetic fields so as to experience no deflection. If E = 15 x 106 V m-1 and B = 5 x103 T , then the specific charge of the particle isa)4.5 x 104 4 C kg-1b)9 x 107 C kg-1c)4.5x 103 C kg-1d)9x105 C kg-1Correct answer is option 'A'. Can you explain this answer?.
Solutions for A charged particale accelerated through a P.D. of 100 volt passes throught the uniform electric and magnetic fields so as to experience no deflection. If E = 15 x 106 V m-1 and B = 5 x103 T , then the specific charge of the particle isa)4.5 x 104 4 C kg-1b)9 x 107 C kg-1c)4.5x 103 C kg-1d)9x105 C kg-1Correct answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
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A charged particale accelerated through a P.D. of 100 volt passes throught the uniform electric and magnetic fields so as to experience no deflection. If E = 15 x 106 V m-1 and B = 5 x103 T , then the specific charge of the particle isa)4.5 x 104 4 C kg-1b)9 x 107 C kg-1c)4.5x 103 C kg-1d)9x105 C kg-1Correct answer is option 'A'. Can you explain this answer?, a detailed solution for A charged particale accelerated through a P.D. of 100 volt passes throught the uniform electric and magnetic fields so as to experience no deflection. If E = 15 x 106 V m-1 and B = 5 x103 T , then the specific charge of the particle isa)4.5 x 104 4 C kg-1b)9 x 107 C kg-1c)4.5x 103 C kg-1d)9x105 C kg-1Correct answer is option 'A'. Can you explain this answer? has been provided alongside types of A charged particale accelerated through a P.D. of 100 volt passes throught the uniform electric and magnetic fields so as to experience no deflection. If E = 15 x 106 V m-1 and B = 5 x103 T , then the specific charge of the particle isa)4.5 x 104 4 C kg-1b)9 x 107 C kg-1c)4.5x 103 C kg-1d)9x105 C kg-1Correct answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
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