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An organic compound containing C, H and O gave on analysis C – 40% and H – 6.66%. Its empirical formula would be [1999, 94]
- a)C3H6O
- b)CHO
- c)CH2O
- d)CH4O
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
An organic compound containing C, H and O gave on analysis C – 4...
(% of O in organic compound Table for empirical formula : = 100 – (40 + 6.66 ) = 53.34 % )
Empirical formula of organic compound = CH2O.
Empirical formula of organic compound = CH2O.
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An organic compound containing C, H and O gave on analysis C – 4...
Analyzing the Composition
To find the empirical formula of the organic compound with 40% carbon (C) and 6.66% hydrogen (H), we first determine the percentage of oxygen (O) in the compound.
- Total percentage of C and H = 40% + 6.66% = 46.66%
- Therefore, percentage of O = 100% - 46.66% = 53.34%
Calculating Moles of Each Element
Next, we convert these percentages into moles:
- Moles of C = 40 g / 12 g/mol = 3.33 moles
- Moles of H = 6.66 g / 1 g/mol = 6.66 moles
- Moles of O = 53.34 g / 16 g/mol = 3.33 moles
Simplifying the Mole Ratios
Now, we simplify the mole ratios by dividing each by the smallest number of moles calculated, which is 3.33:
- Ratio of C = 3.33 / 3.33 = 1
- Ratio of H = 6.66 / 3.33 = 2
- Ratio of O = 3.33 / 3.33 = 1
This gives us the ratio of C:H:O as 1:2:1.
Determining the Empirical Formula
The empirical formula can now be written based on the simplified ratios:
- C1H2O1 or simply CH2O
Verifying the Correct Option
Upon reviewing the options provided:
- a) C3H6O
- b) CHO
- c) CH2O
- d) CH4O
The correct answer is option 'c', CH2O, which corresponds to the calculated empirical formula.
To find the empirical formula of the organic compound with 40% carbon (C) and 6.66% hydrogen (H), we first determine the percentage of oxygen (O) in the compound.
- Total percentage of C and H = 40% + 6.66% = 46.66%
- Therefore, percentage of O = 100% - 46.66% = 53.34%
Calculating Moles of Each Element
Next, we convert these percentages into moles:
- Moles of C = 40 g / 12 g/mol = 3.33 moles
- Moles of H = 6.66 g / 1 g/mol = 6.66 moles
- Moles of O = 53.34 g / 16 g/mol = 3.33 moles
Simplifying the Mole Ratios
Now, we simplify the mole ratios by dividing each by the smallest number of moles calculated, which is 3.33:
- Ratio of C = 3.33 / 3.33 = 1
- Ratio of H = 6.66 / 3.33 = 2
- Ratio of O = 3.33 / 3.33 = 1
This gives us the ratio of C:H:O as 1:2:1.
Determining the Empirical Formula
The empirical formula can now be written based on the simplified ratios:
- C1H2O1 or simply CH2O
Verifying the Correct Option
Upon reviewing the options provided:
- a) C3H6O
- b) CHO
- c) CH2O
- d) CH4O
The correct answer is option 'c', CH2O, which corresponds to the calculated empirical formula.
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An organic compound containing C, H and O gave on analysis C – 40% and H – 6.66%. Its empirical formula would be [1999, 94]a)C3H6Ob)CHOc)CH2Od)CH4OCorrect answer is option 'C'. Can you explain this answer? for Class 11 2025 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about An organic compound containing C, H and O gave on analysis C – 40% and H – 6.66%. Its empirical formula would be [1999, 94]a)C3H6Ob)CHOc)CH2Od)CH4OCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 11 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An organic compound containing C, H and O gave on analysis C – 40% and H – 6.66%. Its empirical formula would be [1999, 94]a)C3H6Ob)CHOc)CH2Od)CH4OCorrect answer is option 'C'. Can you explain this answer?.
An organic compound containing C, H and O gave on analysis C – 40% and H – 6.66%. Its empirical formula would be [1999, 94]a)C3H6Ob)CHOc)CH2Od)CH4OCorrect answer is option 'C'. Can you explain this answer? for Class 11 2025 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about An organic compound containing C, H and O gave on analysis C – 40% and H – 6.66%. Its empirical formula would be [1999, 94]a)C3H6Ob)CHOc)CH2Od)CH4OCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 11 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An organic compound containing C, H and O gave on analysis C – 40% and H – 6.66%. Its empirical formula would be [1999, 94]a)C3H6Ob)CHOc)CH2Od)CH4OCorrect answer is option 'C'. Can you explain this answer?.
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