If angular velocity of a disc depends an angle rotated q as w = q2+ 2q, then its angular acceleration a at q = 1 rad isa)8 rad/sec2b)10 rad/sec2c)12 rad/sec2d)NoneCorrect answer is option 'C'. Can you explain this answer?

Question

Answer

Answer

Answer

Answer

Angular velocity is the rate at which an object rotates around a fixed axis. It is usually denoted by the symbol ω (omega) and is measured in radians per second (rad/s). Angular acceleration, on the other hand, is the rate at which the angular velocity of an object changes. It is denoted by the symbol α (alpha) and is also measured in radians per second squared (rad/s^2).

Given that the angular velocity of the disc is given by the equation ω = q^2 - 2q, where q is the angle rotated in radians, we can find the angular acceleration at q = 1 rad by taking the derivative of the angular velocity equation with respect to time.

To find the angular acceleration, we need to calculate the derivative of ω with respect to q, and then multiply it by the derivative of q with respect to time (which is equal to 1, as q is the angle rotated).

Let's calculate the derivative of ω with respect to q:

dω/dq = 2q - 2

Now, we can substitute q = 1 into the derivative equation to find the angular acceleration at q = 1 rad:

a = 2(1) - 2
a = 2 - 2
a = 0

Oops, it seems like there is a mistake in the options provided. The correct answer should be 'd) None' because the angular acceleration at q = 1 rad is 0 and none of the given options match this value.

Therefore, the correct answer should be 'd) None.'

Top Courses for Class 11View all

Mathematics (Maths) Class 11

Chemistry Class 11

English Snapshot Class 11

CUET Science Subjects Mock Tests 2026

English Class 11

Top Courses for Class 11

Top Courses for Class 11

Related Content

Schools

Competitive Examinations

Quick Access Links

Technical Exams