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Two moles of an aldehyde react with concentrated solution of sodium hydroxide and produce one mole of acid and one mole of alcohol. The aldehyde is
- a)Acetaldehyde, CH₃CHO
- b)Formaldehyde, HCHO
- c)Propionaldehyde, CH₃CH₂CHO
- d)All the three above.
Correct answer is option 'B'. Can you explain this answer?
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Most Upvoted Answer
Two moles of an aldehyde react with concentrated solution of sodium hy...
Its Cannizaro reaction that uses concentrated NaOH. And we also need aldehyde without alpha-H. So, answer is B
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Two moles of an aldehyde react with concentrated solution of sodium hy...
Answer:
To determine which aldehyde is produced when two moles of an aldehyde react with a concentrated solution of sodium hydroxide, we need to understand the reaction between aldehydes and sodium hydroxide.
Reaction between aldehydes and sodium hydroxide:
When an aldehyde reacts with sodium hydroxide, it undergoes a nucleophilic addition reaction. The sodium hydroxide acts as a nucleophile and attacks the carbon atom of the aldehyde, resulting in the formation of a carboxylate ion and an alcohol.
The balanced equation for the reaction can be represented as follows:
RCHO + NaOH → RCOONa + R'OH
Where R represents the alkyl group of the aldehyde, R' represents the alkyl group of the alcohol, and RCOONa represents the carboxylate ion.
Analysis of the given options:
a) Acetaldehyde, CH3CHO
b) Formaldehyde, HCHO
c) Propionaldehyde, CH3CH2CHO
Option A: Acetaldehyde, CH3CHO
If we consider acetaldehyde, the balanced equation for the reaction would be:
CH3CHO + NaOH → CH3COONa + CH3OH
This reaction produces one mole of the carboxylate ion (acid) and one mole of alcohol, satisfying the given condition. Therefore, acetaldehyde is a possible answer.
Option B: Formaldehyde, HCHO
For formaldehyde, the balanced equation for the reaction would be:
HCHO + NaOH → HCOONa + CH3OH
This reaction also produces one mole of the carboxylate ion (acid) and one mole of alcohol, satisfying the given condition. Therefore, formaldehyde is a possible answer.
Option C: Propionaldehyde, CH3CH2CHO
For propionaldehyde, the balanced equation for the reaction would be:
CH3CH2CHO + NaOH → CH3CH2COONa + CH3CH2OH
This reaction produces two moles of the carboxylate ion (acid) and two moles of alcohol, which does not match the given condition. Therefore, propionaldehyde is not a possible answer.
Conclusion:
From the analysis above, we can conclude that the correct answer is option B: Formaldehyde, HCHO.
To determine which aldehyde is produced when two moles of an aldehyde react with a concentrated solution of sodium hydroxide, we need to understand the reaction between aldehydes and sodium hydroxide.
Reaction between aldehydes and sodium hydroxide:
When an aldehyde reacts with sodium hydroxide, it undergoes a nucleophilic addition reaction. The sodium hydroxide acts as a nucleophile and attacks the carbon atom of the aldehyde, resulting in the formation of a carboxylate ion and an alcohol.
The balanced equation for the reaction can be represented as follows:
RCHO + NaOH → RCOONa + R'OH
Where R represents the alkyl group of the aldehyde, R' represents the alkyl group of the alcohol, and RCOONa represents the carboxylate ion.
Analysis of the given options:
a) Acetaldehyde, CH3CHO
b) Formaldehyde, HCHO
c) Propionaldehyde, CH3CH2CHO
Option A: Acetaldehyde, CH3CHO
If we consider acetaldehyde, the balanced equation for the reaction would be:
CH3CHO + NaOH → CH3COONa + CH3OH
This reaction produces one mole of the carboxylate ion (acid) and one mole of alcohol, satisfying the given condition. Therefore, acetaldehyde is a possible answer.
Option B: Formaldehyde, HCHO
For formaldehyde, the balanced equation for the reaction would be:
HCHO + NaOH → HCOONa + CH3OH
This reaction also produces one mole of the carboxylate ion (acid) and one mole of alcohol, satisfying the given condition. Therefore, formaldehyde is a possible answer.
Option C: Propionaldehyde, CH3CH2CHO
For propionaldehyde, the balanced equation for the reaction would be:
CH3CH2CHO + NaOH → CH3CH2COONa + CH3CH2OH
This reaction produces two moles of the carboxylate ion (acid) and two moles of alcohol, which does not match the given condition. Therefore, propionaldehyde is not a possible answer.
Conclusion:
From the analysis above, we can conclude that the correct answer is option B: Formaldehyde, HCHO.
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Two moles of an aldehyde react with concentrated solution of sodium hydroxide and produce one mole of acid and one mole of alcohol. The aldehyde isa)Acetaldehyde, CH₃CHOb)Formaldehyde, HCHOc)Propionaldehyde, CH₃CH₂CHOd)All the three above.Correct answer is option 'B'. Can you explain this answer?
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Two moles of an aldehyde react with concentrated solution of sodium hydroxide and produce one mole of acid and one mole of alcohol. The aldehyde isa)Acetaldehyde, CH₃CHOb)Formaldehyde, HCHOc)Propionaldehyde, CH₃CH₂CHOd)All the three above.Correct answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Two moles of an aldehyde react with concentrated solution of sodium hydroxide and produce one mole of acid and one mole of alcohol. The aldehyde isa)Acetaldehyde, CH₃CHOb)Formaldehyde, HCHOc)Propionaldehyde, CH₃CH₂CHOd)All the three above.Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two moles of an aldehyde react with concentrated solution of sodium hydroxide and produce one mole of acid and one mole of alcohol. The aldehyde isa)Acetaldehyde, CH₃CHOb)Formaldehyde, HCHOc)Propionaldehyde, CH₃CH₂CHOd)All the three above.Correct answer is option 'B'. Can you explain this answer?.
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