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Two moles of an aldehyde react with concentrated solution of sodium hydroxide and produce one mole of acid and one mole of alcohol. The aldehyde is
- a)Acetaldehyde, CH₃CHO
- b)Formaldehyde, HCHO
- c)Propionaldehyde, CH₃CH₂CHO
- d)All the three above.
Correct answer is option 'B'. Can you explain this answer?
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Two moles of an aldehyde react with concentrated solution of sodium hy...
Aldehyde Reaction with Sodium Hydroxide:
When an aldehyde reacts with a concentrated solution of sodium hydroxide, it undergoes a process known as the Cannizzaro reaction. In this reaction, the aldehyde is both oxidized to form the corresponding carboxylic acid and reduced to form the corresponding alcohol.
Identifying the Aldehyde:
Among the options given, the aldehyde that reacts to produce one mole of acid and one mole of alcohol is Formaldehyde, HCHO.
Explanation:
- Acetaldehyde, CH3CHO, will produce acetic acid and ethanol.
- Propionaldehyde, CH3CH2CHO, will produce propionic acid and propanol.
- Formaldehyde, HCHO, is the only aldehyde that will produce formic acid and methanol, as stated in the question.
Therefore, the correct option is 'b) Formaldehyde, HCHO'.
When an aldehyde reacts with a concentrated solution of sodium hydroxide, it undergoes a process known as the Cannizzaro reaction. In this reaction, the aldehyde is both oxidized to form the corresponding carboxylic acid and reduced to form the corresponding alcohol.
Identifying the Aldehyde:
Among the options given, the aldehyde that reacts to produce one mole of acid and one mole of alcohol is Formaldehyde, HCHO.
Explanation:
- Acetaldehyde, CH3CHO, will produce acetic acid and ethanol.
- Propionaldehyde, CH3CH2CHO, will produce propionic acid and propanol.
- Formaldehyde, HCHO, is the only aldehyde that will produce formic acid and methanol, as stated in the question.
Therefore, the correct option is 'b) Formaldehyde, HCHO'.
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Two moles of an aldehyde react with concentrated solution of sodium hydroxide and produce one mole of acid and one mole of alcohol. The aldehyde isa)Acetaldehyde, CHCHOb)Formaldehyde, HCHOc)Propionaldehyde, CHCHCHOd)All the three above.Correct answer is option 'B'. Can you explain this answer?
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