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Let a, b, c be non coplanar unit vectors, making an angle of 60º with each other. If a *b+ b* c =pa qb rc , then the value of 2(p^2 q^2 r^2) is equal to * = here is for cross product?
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?Let a, b, c be non coplanar unit vectors, making an angle of 60º with...
Problem
Let a, b, c be non-coplanar unit vectors, making an angle of 60º with each other. If a * b b * c = pa qb rc, then the value of 2(p^2 q^2 r^2) is equal to what?

Solution
Given:
a, b, c are non-coplanar unit vectors.
The angle between a, b and b, c is 60º.
a * b = |a| |b| sin(θ) n, where θ is the angle between a and b, and n is the unit vector perpendicular to the plane containing a and b.
b * c = |b| |c| sin(ϕ) n', where ϕ is the angle between b and c, and n' is the unit vector perpendicular to the plane containing b and c.
We need to find 2(p^2 q^2 r^2).

Step 1: Find a * b * c.
a * b * c = (a * b) * c = (|a| |b| sin(θ) n) * c
= |a| |b| sin(θ) (n * c)
= -|a| |b| sin(θ) (c * n)
= -a * (b * c)
= -a * (|b| |c| sin(ϕ) n')
= -|a| |b| |c| sin(θ) sin(ϕ) (n * n')

Step 2: Find the value of p, q, and r.
a * b * c = pa qb rc
=> -|a| |b| |c| sin(θ) sin(ϕ) (n * n') = pa qb rc
=> 2(p^2 q^2 r^2) = (sin(θ) sin(ϕ))^2

Step 3: Substitute the values of sin(θ) and sin(ϕ).
sin(θ) = sin(60º) = √3/2
sin(ϕ) = sin(60º) = √3/2
=> 2(p^2 q^2 r^2) = (√3/2)^2 * (√3/2)^2
= 3/4

Therefore, 2(p^2 q^2 r^2) = 3/4, or p^2 q^2 r^2 = 3/8.
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?Let a, b, c be non coplanar unit vectors, making an angle of 60º with each other. If a *b+ b* c =pa qb rc , then the value of 2(p^2 q^2 r^2) is equal to * = here is for cross product?
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