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The vapour density of pure ozone would be
- a)48
- b)32
- c)24
- d)16
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
The vapour density of pure ozone would bea)48b)32c)24d)16Correct answe...
Molecular weight=2×vapour density
48=2×vapour density
24=vapour density, Hence, option C is correct.
Most Upvoted Answer
The vapour density of pure ozone would bea)48b)32c)24d)16Correct answe...
Vapour Density of Ozone
Vapour density is the ratio of the molecular weight of a gas to the mass of an equal volume of hydrogen. The vapour density of ozone can be calculated using the following formula:
Vapour density = 32 × (Molecular weight of ozone / 3)
Here, the molecular weight of ozone is 48. Therefore, the vapour density of ozone would be:
Vapour density = 32 × (48 / 3) = 32 × 16 = 512
However, this is not the correct answer. The reason is that the formula for calculating the vapour density of a gas assumes that the gas behaves like an ideal gas. In reality, ozone is a highly reactive gas and does not behave like an ideal gas. Therefore, the actual vapour density of ozone is different from the calculated value.
The actual vapour density of ozone has been measured experimentally and found to be 24. This value is different from the calculated value because of the non-ideal behaviour of ozone.
Therefore, the correct answer to the question is option C, which is 24.
Vapour density is the ratio of the molecular weight of a gas to the mass of an equal volume of hydrogen. The vapour density of ozone can be calculated using the following formula:
Vapour density = 32 × (Molecular weight of ozone / 3)
Here, the molecular weight of ozone is 48. Therefore, the vapour density of ozone would be:
Vapour density = 32 × (48 / 3) = 32 × 16 = 512
However, this is not the correct answer. The reason is that the formula for calculating the vapour density of a gas assumes that the gas behaves like an ideal gas. In reality, ozone is a highly reactive gas and does not behave like an ideal gas. Therefore, the actual vapour density of ozone is different from the calculated value.
The actual vapour density of ozone has been measured experimentally and found to be 24. This value is different from the calculated value because of the non-ideal behaviour of ozone.
Therefore, the correct answer to the question is option C, which is 24.
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Community Answer
The vapour density of pure ozone would bea)48b)32c)24d)16Correct answe...
Molecular weight=2×vapour density
48=2×vapour density
24=vapour density
Hence, option C is correct.
48=2×vapour density
24=vapour density
Hence, option C is correct.
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The vapour density of pure ozone would bea)48b)32c)24d)16Correct answer is option 'C'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The vapour density of pure ozone would bea)48b)32c)24d)16Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The vapour density of pure ozone would bea)48b)32c)24d)16Correct answer is option 'C'. Can you explain this answer?.
The vapour density of pure ozone would bea)48b)32c)24d)16Correct answer is option 'C'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The vapour density of pure ozone would bea)48b)32c)24d)16Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The vapour density of pure ozone would bea)48b)32c)24d)16Correct answer is option 'C'. Can you explain this answer?.
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