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If 0.183 of an aromatic monobasic acid requires 15ml of N/10 sodium hydroxide for complete neutralisation, then molecular weight of the acid is
- a)56
- b)122
- c)166
- d)224
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
If 0.183 of an aromatic monobasic acid requires 15ml of N/10 sodium hy...
Milliequivalents of NaOH = 15×1/10 = 1.5 = 0.0015 equivalents
For neutralization equivalents of acid = 0.0015
As the acid is monobasic, n factor= 1, so moles of acid required = 0.0015/1 = 0.0015
weight/MW = 0.183g/0.0015 MW
MW= 122g
For neutralization equivalents of acid = 0.0015
As the acid is monobasic, n factor= 1, so moles of acid required = 0.0015/1 = 0.0015
weight/MW = 0.183g/0.0015 MW
MW= 122g
Most Upvoted Answer
If 0.183 of an aromatic monobasic acid requires 15ml of N/10 sodium hy...
Finding the Molecular Weight of an Acid
Given: 0.183 of an aromatic monobasic acid requires 15ml of N/10 sodium hydroxide for complete neutralisation.
To find: Molecular weight of the acid.
Solution:
First, calculate the number of moles of sodium hydroxide used in neutralizing 0.183g of the acid.
Moles of sodium hydroxide = (15/1000) x (1/10) = 0.0015
The number of moles of the acid is equal to the number of moles of sodium hydroxide used.
Moles of acid = 0.0015
Next, calculate the molecular weight of the acid.
Molecular weight = (Weight of acid in grams) / (Number of moles of acid)
Weight of the acid = 0.183g
Number of moles of acid = 0.0015
Molecular weight = 0.183 / 0.0015 = 122
Therefore, the molecular weight of the acid is 122.
Answer: (b) 122
Given: 0.183 of an aromatic monobasic acid requires 15ml of N/10 sodium hydroxide for complete neutralisation.
To find: Molecular weight of the acid.
Solution:
First, calculate the number of moles of sodium hydroxide used in neutralizing 0.183g of the acid.
Moles of sodium hydroxide = (15/1000) x (1/10) = 0.0015
The number of moles of the acid is equal to the number of moles of sodium hydroxide used.
Moles of acid = 0.0015
Next, calculate the molecular weight of the acid.
Molecular weight = (Weight of acid in grams) / (Number of moles of acid)
Weight of the acid = 0.183g
Number of moles of acid = 0.0015
Molecular weight = 0.183 / 0.0015 = 122
Therefore, the molecular weight of the acid is 122.
Answer: (b) 122
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Community Answer
If 0.183 of an aromatic monobasic acid requires 15ml of N/10 sodium hy...
Milliequivalents of NaOH = 15×1/10 = 1.5 = 0.0015 equivalents
For neutralization equivalents of acid = 0.0015
As the acid is monobasic, n factor= 1, so moles of acid required = 0.0015/1 = 0.0015
0.0015 = given weight/MW = 0.183g/MW
MW= 122g
For neutralization equivalents of acid = 0.0015
As the acid is monobasic, n factor= 1, so moles of acid required = 0.0015/1 = 0.0015
0.0015 = given weight/MW = 0.183g/MW
MW= 122g
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