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The maximum amount of BaSO₄ precipitated on mixing BaCl₂ (0.5M) with H₂SO₄ (1 M0 will correspond to
- a)0.5 M
- b)1.0 M
- c)1.5 M
- d)2.0 M
Correct answer is option 'A'. Can you explain this answer?
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The maximum amount of BaSO₄ precipitated on mixing BaCl₂ (...
BaSO4 Precipitation Reaction
The precipitation reaction between BaCl2 and H2SO4 can be represented as follows:
BaCl2 (aq) + H2SO4 (aq) → BaSO4 (s) + 2HCl (aq)
In this reaction, BaSO4 is the insoluble precipitate that is formed.
Factors Affecting Precipitation
The amount of BaSO4 that can be precipitated depends on the following factors:
- The concentration of BaCl2 solution
- The concentration of H2SO4 solution
- The stoichiometry of the reaction
Maximum Amount of BaSO4 Precipitated
To determine the maximum amount of BaSO4 that can be precipitated, we need to calculate the limiting reagent and the amount of product that can be formed from it.
- Limiting Reagent: The limiting reagent is the reactant that is completely consumed in the reaction. To determine the limiting reagent, we need to calculate the moles of each reactant and compare them to the stoichiometry of the reaction.
BaCl2 (0.5 M) → moles = 0.5 x volume (L)
HSO4- (1 M) → moles = 1 x volume (L)
From the balanced equation, we can see that 1 mole of BaCl2 reacts with 1 mole of H2SO4. Therefore, the limiting reagent is the reactant that has the lowest number of moles.
- Amount of Product: The amount of product that can be formed is determined by the limiting reagent. In this case, since 1 mole of BaCl2 reacts with 1 mole of H2SO4, the maximum amount of BaSO4 that can be formed is equal to the number of moles of BaCl2.
Therefore, the maximum amount of BaSO4 that can be precipitated on mixing BaCl2 (0.5 M) with H2SO4 (1 M) is 0.5 M.
Conclusion
The maximum amount of BaSO4 that can be precipitated on mixing BaCl2 (0.5 M) with H2SO4 (1 M) is 0.5 M, which is equal to the concentration of BaCl2. This is because BaCl2 is the limiting reagent, and the amount of product that can be formed is determined by the limiting reagent.
The precipitation reaction between BaCl2 and H2SO4 can be represented as follows:
BaCl2 (aq) + H2SO4 (aq) → BaSO4 (s) + 2HCl (aq)
In this reaction, BaSO4 is the insoluble precipitate that is formed.
Factors Affecting Precipitation
The amount of BaSO4 that can be precipitated depends on the following factors:
- The concentration of BaCl2 solution
- The concentration of H2SO4 solution
- The stoichiometry of the reaction
Maximum Amount of BaSO4 Precipitated
To determine the maximum amount of BaSO4 that can be precipitated, we need to calculate the limiting reagent and the amount of product that can be formed from it.
- Limiting Reagent: The limiting reagent is the reactant that is completely consumed in the reaction. To determine the limiting reagent, we need to calculate the moles of each reactant and compare them to the stoichiometry of the reaction.
BaCl2 (0.5 M) → moles = 0.5 x volume (L)
HSO4- (1 M) → moles = 1 x volume (L)
From the balanced equation, we can see that 1 mole of BaCl2 reacts with 1 mole of H2SO4. Therefore, the limiting reagent is the reactant that has the lowest number of moles.
- Amount of Product: The amount of product that can be formed is determined by the limiting reagent. In this case, since 1 mole of BaCl2 reacts with 1 mole of H2SO4, the maximum amount of BaSO4 that can be formed is equal to the number of moles of BaCl2.
Therefore, the maximum amount of BaSO4 that can be precipitated on mixing BaCl2 (0.5 M) with H2SO4 (1 M) is 0.5 M.
Conclusion
The maximum amount of BaSO4 that can be precipitated on mixing BaCl2 (0.5 M) with H2SO4 (1 M) is 0.5 M, which is equal to the concentration of BaCl2. This is because BaCl2 is the limiting reagent, and the amount of product that can be formed is determined by the limiting reagent.
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The maximum amount of BaSO₄ precipitated on mixing BaCl₂ (...
BaCl2 is the limiting reagent bcoz for 1 mole of H2SO4, only 0.5 mole of BaCl2 is present. The amount of product formed is always decided by the amount of that reactant which is the least.
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The maximum amount of BaSO₄ precipitated on mixing BaCl₂ (0.5M) with H₂SO₄ (1 M0 will correspond toa)0.5 Mb)1.0 Mc)1.5 Md)2.0 MCorrect answer is option 'A'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The maximum amount of BaSO₄ precipitated on mixing BaCl₂ (0.5M) with H₂SO₄ (1 M0 will correspond toa)0.5 Mb)1.0 Mc)1.5 Md)2.0 MCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The maximum amount of BaSO₄ precipitated on mixing BaCl₂ (0.5M) with H₂SO₄ (1 M0 will correspond toa)0.5 Mb)1.0 Mc)1.5 Md)2.0 MCorrect answer is option 'A'. Can you explain this answer?.
The maximum amount of BaSO₄ precipitated on mixing BaCl₂ (0.5M) with H₂SO₄ (1 M0 will correspond toa)0.5 Mb)1.0 Mc)1.5 Md)2.0 MCorrect answer is option 'A'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The maximum amount of BaSO₄ precipitated on mixing BaCl₂ (0.5M) with H₂SO₄ (1 M0 will correspond toa)0.5 Mb)1.0 Mc)1.5 Md)2.0 MCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The maximum amount of BaSO₄ precipitated on mixing BaCl₂ (0.5M) with H₂SO₄ (1 M0 will correspond toa)0.5 Mb)1.0 Mc)1.5 Md)2.0 MCorrect answer is option 'A'. Can you explain this answer?.
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