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A force of 750 N is applied to a block of mass 102 kg to prevent it form sliding on a plane with an inclination angle 30° with the horizontal. If the coefficients of static friction and kinetic friction between the block and the plane are 0.4 and 0.3 respectively, then the frictional force acting on the block is
- a)750 N
- b)500 N
- c)345 N
- d)250 N
Correct answer is option 'D'. Can you explain this answer?
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First, we need to find the force of gravity acting on the block, which is given by:
F_gravity = m * g
where m is the mass of the block and g is the acceleration due to gravity (9.81 m/s^2).
F_gravity = 102 kg * 9.81 m/s^2 = 999.62 N
Next, we need to find the component of the force of gravity acting parallel to the plane, which is given by:
F_parallel = F_gravity * sin(30°)
F_parallel = 999.62 N * sin(30°) = 499.81 N
Finally, we need to apply a force equal and opposite to the parallel component of the force of gravity to prevent the block from sliding.
F_applied = F_parallel = 499.81 N
Therefore, the force that needs to be applied to the block to prevent it from sliding on the inclined plane is 499.81 N. The force of 750 N is more than enough to prevent the block from sliding.
First, we need to find the force of gravity acting on the block, which is given by:
F_gravity = m * g
where m is the mass of the block and g is the acceleration due to gravity (9.81 m/s^2).
F_gravity = 102 kg * 9.81 m/s^2 = 999.62 N
Next, we need to find the component of the force of gravity acting parallel to the plane, which is given by:
F_parallel = F_gravity * sin(30°)
F_parallel = 999.62 N * sin(30°) = 499.81 N
Finally, we need to apply a force equal and opposite to the parallel component of the force of gravity to prevent the block from sliding.
F_applied = F_parallel = 499.81 N
Therefore, the force that needs to be applied to the block to prevent it from sliding on the inclined plane is 499.81 N. The force of 750 N is more than enough to prevent the block from sliding.
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A force of 750 N is applied to a block of mass 102 kg to prevent it form sliding on a plane with an inclination angle 30° with the horizontal. If the coefficients of static friction and kinetic friction between the block and the plane are 0.4 and 0.3 respectively, then the frictional force acting on the block isa)750 Nb)500 Nc)345 Nd)250 NCorrect answer is option 'D'. Can you explain this answer?
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A force of 750 N is applied to a block of mass 102 kg to prevent it form sliding on a plane with an inclination angle 30° with the horizontal. If the coefficients of static friction and kinetic friction between the block and the plane are 0.4 and 0.3 respectively, then the frictional force acting on the block isa)750 Nb)500 Nc)345 Nd)250 NCorrect answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A force of 750 N is applied to a block of mass 102 kg to prevent it form sliding on a plane with an inclination angle 30° with the horizontal. If the coefficients of static friction and kinetic friction between the block and the plane are 0.4 and 0.3 respectively, then the frictional force acting on the block isa)750 Nb)500 Nc)345 Nd)250 NCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A force of 750 N is applied to a block of mass 102 kg to prevent it form sliding on a plane with an inclination angle 30° with the horizontal. If the coefficients of static friction and kinetic friction between the block and the plane are 0.4 and 0.3 respectively, then the frictional force acting on the block isa)750 Nb)500 Nc)345 Nd)250 NCorrect answer is option 'D'. Can you explain this answer?.
A force of 750 N is applied to a block of mass 102 kg to prevent it form sliding on a plane with an inclination angle 30° with the horizontal. If the coefficients of static friction and kinetic friction between the block and the plane are 0.4 and 0.3 respectively, then the frictional force acting on the block isa)750 Nb)500 Nc)345 Nd)250 NCorrect answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A force of 750 N is applied to a block of mass 102 kg to prevent it form sliding on a plane with an inclination angle 30° with the horizontal. If the coefficients of static friction and kinetic friction between the block and the plane are 0.4 and 0.3 respectively, then the frictional force acting on the block isa)750 Nb)500 Nc)345 Nd)250 NCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A force of 750 N is applied to a block of mass 102 kg to prevent it form sliding on a plane with an inclination angle 30° with the horizontal. If the coefficients of static friction and kinetic friction between the block and the plane are 0.4 and 0.3 respectively, then the frictional force acting on the block isa)750 Nb)500 Nc)345 Nd)250 NCorrect answer is option 'D'. Can you explain this answer?.
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