A six-faced dice is so biased that it is twice as likely to show an ev...
∵ probability for odd = p
∴ probability for even = 2p
∵ p + 2p = 1
⇒ 3p = 1
⇒ p = 1/3
∴ probability for odd = 1/3 , probability for even = 2/3
Sum of two no. is even means either both are odd or both are even
∴ required probability = (1/3 × 1/3) + (2/3 × 2/3) = 1/9 + 4/9 = 5/9
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A six-faced dice is so biased that it is twice as likely to show an ev...
A six-faced dice is so biased that it is twice as likely to show an ev...
Given information:
- A six-faced dice is biased and twice as likely to show an even number as an odd number when thrown.
To find:
The probability that the sum of two numbers thrown is even when the biased dice is thrown twice.
Solution:
Let's analyze the possible outcomes when a biased dice is thrown twice. We can represent the numbers on the dice as {1, 2, 3, 4, 5, 6}.
Even numbers:
The biased dice is twice as likely to show an even number. Therefore, the probabilities of getting each even number are {2/9, 4/9, 2/9} (total probabilities add up to 2/3).
Odd numbers:
The biased dice is half as likely to show an odd number. Therefore, the probabilities of getting each odd number are {1/9, 2/9, 1/9} (total probabilities add up to 1/3).
Now, let's consider the possible outcomes when the dice is thrown twice:
Even + Even:
- The probability of getting an even number on the first throw is 2/3.
- The probability of getting an even number on the second throw is also 2/3.
- Therefore, the probability of getting an even sum is (2/3) * (2/3) = 4/9.
Even + Odd:
- The probability of getting an even number on the first throw is 2/3.
- The probability of getting an odd number on the second throw is 1/3.
- Therefore, the probability of getting an even sum is (2/3) * (1/3) = 2/9.
Odd + Even:
- The probability of getting an odd number on the first throw is 1/3.
- The probability of getting an even number on the second throw is 2/3.
- Therefore, the probability of getting an even sum is (1/3) * (2/3) = 2/9.
Odd + Odd:
- The probability of getting an odd number on the first throw is 1/3.
- The probability of getting an odd number on the second throw is also 1/3.
- Therefore, the probability of getting an even sum is (1/3) * (1/3) = 1/9.
Total probability of getting an even sum:
To find the total probability of getting an even sum, we add the probabilities of the three cases where the sum is even:
4/9 + 2/9 + 2/9 = 8/9.
Therefore, the probability that the sum of two numbers thrown with the biased dice is even is 8/9, which is not listed among the given answer options. Hence, there seems to be an error in the options provided.
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