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A six-faced dice is so biased that it is twice as likely to show an even number as an odd number when thrown. It is thrown twice. The probability that the sum of two numbers thrown is even is
  • a)
    1/12
  • b)
    1/6
  • c)
    1/3
  • d)
    5/9
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
A six-faced dice is so biased that it is twice as likely to show an ev...
∵ probability for odd = p
∴ probability for even = 2p
∵ p + 2p = 1
⇒ 3p = 1
⇒ p = 1/3​
∴ probability for odd = 1/3​ , probability for even = 2/3​
Sum of two no. is even means either both are odd or both are even
∴ required probability = (1/3​ × 1/3)​ + (2/3 ​× 2/3) ​= 1/9 ​+ 4/9 ​= 5/9​
 
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A six-faced dice is so biased that it is twice as likely to show an ev...
Given information:
- A six-faced dice is biased and twice as likely to show an even number as an odd number when thrown.

To find:
The probability that the sum of two numbers thrown is even when the biased dice is thrown twice.

Solution:
Let's analyze the possible outcomes when a biased dice is thrown twice. We can represent the numbers on the dice as {1, 2, 3, 4, 5, 6}.

Even numbers:
The biased dice is twice as likely to show an even number. Therefore, the probabilities of getting each even number are {2/9, 4/9, 2/9} (total probabilities add up to 2/3).

Odd numbers:
The biased dice is half as likely to show an odd number. Therefore, the probabilities of getting each odd number are {1/9, 2/9, 1/9} (total probabilities add up to 1/3).

Now, let's consider the possible outcomes when the dice is thrown twice:

Even + Even:
- The probability of getting an even number on the first throw is 2/3.
- The probability of getting an even number on the second throw is also 2/3.
- Therefore, the probability of getting an even sum is (2/3) * (2/3) = 4/9.

Even + Odd:
- The probability of getting an even number on the first throw is 2/3.
- The probability of getting an odd number on the second throw is 1/3.
- Therefore, the probability of getting an even sum is (2/3) * (1/3) = 2/9.

Odd + Even:
- The probability of getting an odd number on the first throw is 1/3.
- The probability of getting an even number on the second throw is 2/3.
- Therefore, the probability of getting an even sum is (1/3) * (2/3) = 2/9.

Odd + Odd:
- The probability of getting an odd number on the first throw is 1/3.
- The probability of getting an odd number on the second throw is also 1/3.
- Therefore, the probability of getting an even sum is (1/3) * (1/3) = 1/9.

Total probability of getting an even sum:
To find the total probability of getting an even sum, we add the probabilities of the three cases where the sum is even:
4/9 + 2/9 + 2/9 = 8/9.

Therefore, the probability that the sum of two numbers thrown with the biased dice is even is 8/9, which is not listed among the given answer options. Hence, there seems to be an error in the options provided.
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A six-faced dice is so biased that it is twice as likely to show an even number as an odd number when thrown. It is thrown twice. The probability that the sum of two numbers thrown is even isa)1/12b)1/6c)1/3d)5/9Correct answer is option 'D'. Can you explain this answer?
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