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Two bodies of mass 3 kg and 4 kg are suspended at the ends of massless string passing over a frictionless pulley. The acceleration of the system is (g=9.8 m/s2)
  • a)
    4.9 m/s2
  • b)
    2.45 m/s2
  • c)
    1.4 m/s2
  • d)
    9.8 m/s2
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
Two bodies of mass 3 kg and 4 kg are suspended at the ends of massless...
Given data:
Mass of first body, m1 = 3 kg
Mass of second body, m2 = 4 kg
Acceleration, a = ?
Gravitational acceleration, g = 9.8 m/s²

Let's assume that the direction of motion of m2 is downwards and that of m1 is upwards.

Applying Newton's laws of motion:
For m1: T - m1g = m1a (1)
For m2: m2g - T = m2a (2)
where T is the tension in the string.

Adding equations (1) and (2), we get:
m2g - m1g = (m1 + m2)a
a = (m2g - m1g) / (m1 + m2)
On substituting the given values, we get:
a = (4 × 9.8 - 3 × 9.8) / (3 + 4) = 1.4 m/s²

Therefore, the correct option is (c) 1.4 m/s²
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Two bodies of mass 3 kg and 4 kg are suspended at the ends of massless string passing over a frictionless pulley. The acceleration of the system is (g=9.8 m/s2)a)4.9 m/s2b)2.45 m/s2c)1.4 m/s2d)9.8 m/s2Correct answer is option 'C'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Two bodies of mass 3 kg and 4 kg are suspended at the ends of massless string passing over a frictionless pulley. The acceleration of the system is (g=9.8 m/s2)a)4.9 m/s2b)2.45 m/s2c)1.4 m/s2d)9.8 m/s2Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two bodies of mass 3 kg and 4 kg are suspended at the ends of massless string passing over a frictionless pulley. The acceleration of the system is (g=9.8 m/s2)a)4.9 m/s2b)2.45 m/s2c)1.4 m/s2d)9.8 m/s2Correct answer is option 'C'. Can you explain this answer?.
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