A Bus moving with a velocity of 60 kps is brought to rest in 20 second...
U = 60km/hr × 5/18 = 50/3 m/sec
v = 0
t = 20s
a = ?
we know that-
a = v-u/t
a = -50/3 /20
a = -50/60
∴ a = -0.83m/sec²
negative sign shows that it is a retarded motion.
so its acceleration is 0.83 m/sec²..
A Bus moving with a velocity of 60 kps is brought to rest in 20 second...
Calculating Acceleration of the Bus
To calculate the acceleration of the bus, we need to use the formula:
Acceleration = (Final Velocity - Initial Velocity) / Time Taken
Here, the initial velocity is 60 kps (kilometers per second) since that is the velocity at which the bus is moving before the brakes are applied. The final velocity is 0 kps since the bus comes to a complete stop. The time taken is 20 seconds.
Substituting these values into the formula, we get:
Acceleration = (0 kps - 60 kps) / 20 s
Acceleration = -3 kps^2
Explaining the Calculation
The negative sign in the answer indicates that the acceleration is in the opposite direction to the initial velocity of the bus. This is because the brakes are being applied to slow down the bus, so the acceleration is acting in the opposite direction to the motion of the bus.
The unit of acceleration is kilometers per second squared (kps^2). This means that for every second the bus is slowing down by 3 kilometers per second.
Conclusion
In conclusion, the acceleration of the bus when the brakes are applied is -3 kps^2. This value tells us how quickly the bus is slowing down and in which direction. It is important to note that the braking distance of the bus will depend on several other factors such as the condition of the brakes, the weight of the bus, and the friction between the tires and the road.
To make sure you are not studying endlessly, EduRev has designed Class 9 study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Class 9.