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Statement I : When CH3CH2I is treated with a saturated AgCN solution, CH3CH2NC is formed as the major product.
Statement II : Cyanide is an ambident ligand.
- a)Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement I
- b)Both Statement I and Statement II are correct but Statement II is not the correct explanation of Statement I
- c)Statement I is correct but Statement II is incorrect
- d)Statement II is correct but Statement I is incorrect
Correct answer is option 'B'. Can you explain this answer?
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Statement I : When CH3CH2I is treated with a saturated AgCN solution, ...
Ag—C bond is covalent in AgCN, hence nucle ophilic attacks occur from nitrogen atom.
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Statement I : When CH3CH2I is treated with a saturated AgCN solution, ...
Statement I : When CH3CH2I is treated with a saturated AgCN solution, CH3CH2NC is formed as the major product.
When CH3CH2I is treated with a saturated AgCN solution, the reaction proceeds as follows:
CH3CH2I + AgCN → CH3CH2NC + AgI
Therefore, Statement I is correct.
Statement II : Cyanide is an ambident ligand.
An ambident ligand is a ligand that can bind to a metal ion through different atoms. Cyanide (CN-) can bind to a metal ion through either the carbon atom or the nitrogen atom. Hence, it is an ambident ligand.
Therefore, Statement II is correct.
Explanation:
When CH3CH2I is treated with a saturated AgCN solution, the reaction takes place through a nucleophilic substitution reaction. The nucleophile is CN- and it attacks the carbon atom of CH3CH2I. This leads to the formation of CH3CH2NC as the major product. The silver ion Ag+ is a spectator ion and does not participate in the reaction.
Cyanide (CN-) is an ambident ligand because it can bind to a metal ion through either the carbon atom or the nitrogen atom. The carbon atom forms a coordinate bond with the metal ion, whereas the nitrogen atom donates its lone pair of electrons to form a coordinate bond. This flexibility in binding modes is characteristic of ambident ligands.
In the given reaction, the cyanide ion (CN-) acts as a nucleophile and attacks the carbon atom of CH3CH2I. This results in the formation of CH3CH2NC as the major product. The silver ion (Ag+) from AgCN is not directly involved in the reaction but serves as a counterion to balance the charge.
Hence, both Statement I and Statement II are correct. Statement II is the correct explanation of Statement I because the ability of cyanide to bind through different atoms (carbon or nitrogen) explains why CH3CH2NC is formed as the major product in the reaction between CH3CH2I and AgCN.
When CH3CH2I is treated with a saturated AgCN solution, the reaction proceeds as follows:
CH3CH2I + AgCN → CH3CH2NC + AgI
Therefore, Statement I is correct.
Statement II : Cyanide is an ambident ligand.
An ambident ligand is a ligand that can bind to a metal ion through different atoms. Cyanide (CN-) can bind to a metal ion through either the carbon atom or the nitrogen atom. Hence, it is an ambident ligand.
Therefore, Statement II is correct.
Explanation:
When CH3CH2I is treated with a saturated AgCN solution, the reaction takes place through a nucleophilic substitution reaction. The nucleophile is CN- and it attacks the carbon atom of CH3CH2I. This leads to the formation of CH3CH2NC as the major product. The silver ion Ag+ is a spectator ion and does not participate in the reaction.
Cyanide (CN-) is an ambident ligand because it can bind to a metal ion through either the carbon atom or the nitrogen atom. The carbon atom forms a coordinate bond with the metal ion, whereas the nitrogen atom donates its lone pair of electrons to form a coordinate bond. This flexibility in binding modes is characteristic of ambident ligands.
In the given reaction, the cyanide ion (CN-) acts as a nucleophile and attacks the carbon atom of CH3CH2I. This results in the formation of CH3CH2NC as the major product. The silver ion (Ag+) from AgCN is not directly involved in the reaction but serves as a counterion to balance the charge.
Hence, both Statement I and Statement II are correct. Statement II is the correct explanation of Statement I because the ability of cyanide to bind through different atoms (carbon or nitrogen) explains why CH3CH2NC is formed as the major product in the reaction between CH3CH2I and AgCN.
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Statement I : When CH3CH2I is treated with a saturated AgCN solution, CH3CH2NC is formed as the major product.Statement II : Cyanide is an ambident ligand.a)Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement Ib)Both Statement I and Statement II are correct but Statement II is not the correct explanation of Statement Ic)Statement I is correct but Statement II is incorrectd)Statement II is correct but Statement I is incorrectCorrect answer is option 'B'. Can you explain this answer?
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Statement I : When CH3CH2I is treated with a saturated AgCN solution, CH3CH2NC is formed as the major product.Statement II : Cyanide is an ambident ligand.a)Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement Ib)Both Statement I and Statement II are correct but Statement II is not the correct explanation of Statement Ic)Statement I is correct but Statement II is incorrectd)Statement II is correct but Statement I is incorrectCorrect answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Statement I : When CH3CH2I is treated with a saturated AgCN solution, CH3CH2NC is formed as the major product.Statement II : Cyanide is an ambident ligand.a)Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement Ib)Both Statement I and Statement II are correct but Statement II is not the correct explanation of Statement Ic)Statement I is correct but Statement II is incorrectd)Statement II is correct but Statement I is incorrectCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Statement I : When CH3CH2I is treated with a saturated AgCN solution, CH3CH2NC is formed as the major product.Statement II : Cyanide is an ambident ligand.a)Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement Ib)Both Statement I and Statement II are correct but Statement II is not the correct explanation of Statement Ic)Statement I is correct but Statement II is incorrectd)Statement II is correct but Statement I is incorrectCorrect answer is option 'B'. Can you explain this answer?.
Statement I : When CH3CH2I is treated with a saturated AgCN solution, CH3CH2NC is formed as the major product.Statement II : Cyanide is an ambident ligand.a)Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement Ib)Both Statement I and Statement II are correct but Statement II is not the correct explanation of Statement Ic)Statement I is correct but Statement II is incorrectd)Statement II is correct but Statement I is incorrectCorrect answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Statement I : When CH3CH2I is treated with a saturated AgCN solution, CH3CH2NC is formed as the major product.Statement II : Cyanide is an ambident ligand.a)Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement Ib)Both Statement I and Statement II are correct but Statement II is not the correct explanation of Statement Ic)Statement I is correct but Statement II is incorrectd)Statement II is correct but Statement I is incorrectCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Statement I : When CH3CH2I is treated with a saturated AgCN solution, CH3CH2NC is formed as the major product.Statement II : Cyanide is an ambident ligand.a)Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement Ib)Both Statement I and Statement II are correct but Statement II is not the correct explanation of Statement Ic)Statement I is correct but Statement II is incorrectd)Statement II is correct but Statement I is incorrectCorrect answer is option 'B'. Can you explain this answer?.
Solutions for Statement I : When CH3CH2I is treated with a saturated AgCN solution, CH3CH2NC is formed as the major product.Statement II : Cyanide is an ambident ligand.a)Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement Ib)Both Statement I and Statement II are correct but Statement II is not the correct explanation of Statement Ic)Statement I is correct but Statement II is incorrectd)Statement II is correct but Statement I is incorrectCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
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