JEE Exam > JEE Questions > Statement I : Ethyl acetoacetate (CH3COCH2COO...
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Statement I : Ethyl acetoacetate (CH3COCH2COOC2H5) is very sparingly soluble in pure water and highly soluble in aqueous KOH solution.
Statement II : It’s methylenic (—CH2—) hydrogen is sufficiently acidic, forms salt with KOH quantitatively.
- a)Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement I
- b)Both Statement I and Statement II are correct but Statement II is not the correct explanation of Statement I
- c)Statement I is correct but Statement II is incorrect
- d)Statement II is correct but Statement I is incorrect
Correct answer is option 'A'. Can you explain this answer?
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Statement I : Ethyl acetoacetate (CH3COCH2COOC2H5) is very sparingly s...
Formation of above salt is responsible for solubility.
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Statement I : Ethyl acetoacetate (CH3COCH2COOC2H5) is very sparingly s...
Statement I: Ethyl acetoacetate (CH3COCH2COOC2H5) is very sparingly soluble in pure water and highly soluble in aqueous KOH solution.
Statement II: Its methylenic (CH2) hydrogen is sufficiently acidic, forms salt with KOH quantitatively.
Explanation:
Statement I: Ethyl acetoacetate is a compound with two polar functional groups - a carbonyl group (C=O) and an ester group (COC). However, it also has a nonpolar ethyl (C2H5) group. When ethyl acetoacetate is added to pure water, the polar functional groups can form hydrogen bonds with water molecules, but the nonpolar group cannot. As a result, the compound has low solubility in pure water.
Statement II: The methylenic (CH2) hydrogen in ethyl acetoacetate is sufficiently acidic. This means that it can easily donate a proton (H+) to a base such as KOH. When ethyl acetoacetate is dissolved in aqueous KOH solution, the methylenic hydrogen can react with the hydroxide ion (OH-) from KOH to form water, and the ethyl acetoacetate anion (CH3COCHCOO-) is formed. This anion is stable and soluble in the aqueous solution, leading to the high solubility of ethyl acetoacetate in aqueous KOH solution.
Explanation of the relationship: Both Statement I and Statement II are correct, and Statement II is the correct explanation of Statement I. The low solubility of ethyl acetoacetate in pure water is due to the nonpolar ethyl group, while its high solubility in aqueous KOH solution is due to the formation of the soluble anion through the deprotonation of the methylenic hydrogen.
Therefore, the correct answer is option 'A'.
Statement II: Its methylenic (CH2) hydrogen is sufficiently acidic, forms salt with KOH quantitatively.
Explanation:
Statement I: Ethyl acetoacetate is a compound with two polar functional groups - a carbonyl group (C=O) and an ester group (COC). However, it also has a nonpolar ethyl (C2H5) group. When ethyl acetoacetate is added to pure water, the polar functional groups can form hydrogen bonds with water molecules, but the nonpolar group cannot. As a result, the compound has low solubility in pure water.
Statement II: The methylenic (CH2) hydrogen in ethyl acetoacetate is sufficiently acidic. This means that it can easily donate a proton (H+) to a base such as KOH. When ethyl acetoacetate is dissolved in aqueous KOH solution, the methylenic hydrogen can react with the hydroxide ion (OH-) from KOH to form water, and the ethyl acetoacetate anion (CH3COCHCOO-) is formed. This anion is stable and soluble in the aqueous solution, leading to the high solubility of ethyl acetoacetate in aqueous KOH solution.
Explanation of the relationship: Both Statement I and Statement II are correct, and Statement II is the correct explanation of Statement I. The low solubility of ethyl acetoacetate in pure water is due to the nonpolar ethyl group, while its high solubility in aqueous KOH solution is due to the formation of the soluble anion through the deprotonation of the methylenic hydrogen.
Therefore, the correct answer is option 'A'.
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Statement I : Ethyl acetoacetate (CH3COCH2COOC2H5) is very sparingly soluble in pure water and highly soluble in aqueous KOH solution.Statement II : Its methylenic (CH2) hydrogen is sufficiently acidic, forms salt with KOH quantitatively.a)Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement Ib)Both Statement I and Statement II are correct but Statement II is not the correct explanation of Statement Ic)Statement I is correct but Statement II is incorrectd)Statement II is correct but Statement I is incorrectCorrect answer is option 'A'. Can you explain this answer?
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Statement I : Ethyl acetoacetate (CH3COCH2COOC2H5) is very sparingly soluble in pure water and highly soluble in aqueous KOH solution.Statement II : Its methylenic (CH2) hydrogen is sufficiently acidic, forms salt with KOH quantitatively.a)Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement Ib)Both Statement I and Statement II are correct but Statement II is not the correct explanation of Statement Ic)Statement I is correct but Statement II is incorrectd)Statement II is correct but Statement I is incorrectCorrect answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Statement I : Ethyl acetoacetate (CH3COCH2COOC2H5) is very sparingly soluble in pure water and highly soluble in aqueous KOH solution.Statement II : Its methylenic (CH2) hydrogen is sufficiently acidic, forms salt with KOH quantitatively.a)Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement Ib)Both Statement I and Statement II are correct but Statement II is not the correct explanation of Statement Ic)Statement I is correct but Statement II is incorrectd)Statement II is correct but Statement I is incorrectCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Statement I : Ethyl acetoacetate (CH3COCH2COOC2H5) is very sparingly soluble in pure water and highly soluble in aqueous KOH solution.Statement II : Its methylenic (CH2) hydrogen is sufficiently acidic, forms salt with KOH quantitatively.a)Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement Ib)Both Statement I and Statement II are correct but Statement II is not the correct explanation of Statement Ic)Statement I is correct but Statement II is incorrectd)Statement II is correct but Statement I is incorrectCorrect answer is option 'A'. Can you explain this answer?.
Statement I : Ethyl acetoacetate (CH3COCH2COOC2H5) is very sparingly soluble in pure water and highly soluble in aqueous KOH solution.Statement II : Its methylenic (CH2) hydrogen is sufficiently acidic, forms salt with KOH quantitatively.a)Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement Ib)Both Statement I and Statement II are correct but Statement II is not the correct explanation of Statement Ic)Statement I is correct but Statement II is incorrectd)Statement II is correct but Statement I is incorrectCorrect answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Statement I : Ethyl acetoacetate (CH3COCH2COOC2H5) is very sparingly soluble in pure water and highly soluble in aqueous KOH solution.Statement II : Its methylenic (CH2) hydrogen is sufficiently acidic, forms salt with KOH quantitatively.a)Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement Ib)Both Statement I and Statement II are correct but Statement II is not the correct explanation of Statement Ic)Statement I is correct but Statement II is incorrectd)Statement II is correct but Statement I is incorrectCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Statement I : Ethyl acetoacetate (CH3COCH2COOC2H5) is very sparingly soluble in pure water and highly soluble in aqueous KOH solution.Statement II : Its methylenic (CH2) hydrogen is sufficiently acidic, forms salt with KOH quantitatively.a)Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement Ib)Both Statement I and Statement II are correct but Statement II is not the correct explanation of Statement Ic)Statement I is correct but Statement II is incorrectd)Statement II is correct but Statement I is incorrectCorrect answer is option 'A'. Can you explain this answer?.
Solutions for Statement I : Ethyl acetoacetate (CH3COCH2COOC2H5) is very sparingly soluble in pure water and highly soluble in aqueous KOH solution.Statement II : Its methylenic (CH2) hydrogen is sufficiently acidic, forms salt with KOH quantitatively.a)Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement Ib)Both Statement I and Statement II are correct but Statement II is not the correct explanation of Statement Ic)Statement I is correct but Statement II is incorrectd)Statement II is correct but Statement I is incorrectCorrect answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
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ample number of questions to practice Statement I : Ethyl acetoacetate (CH3COCH2COOC2H5) is very sparingly soluble in pure water and highly soluble in aqueous KOH solution.Statement II : Its methylenic (CH2) hydrogen is sufficiently acidic, forms salt with KOH quantitatively.a)Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement Ib)Both Statement I and Statement II are correct but Statement II is not the correct explanation of Statement Ic)Statement I is correct but Statement II is incorrectd)Statement II is correct but Statement I is incorrectCorrect answer is option 'A'. Can you explain this answer? tests, examples and also practice JEE tests.
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