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Reaction of x g of Sn with HCl quantitatively produced a salt. Entire amount of the salt reacted with y g of nitrobenzene in the presence of required amount of HCl to produce 1.29 g of an organic salt (quantitatively).
(Use Molar masses (in g mol-1) of H, C, N, O, Cl and Sn as 1, 12, 14, 16, 35 and 119, respectively)
Q. The value of y is _______.
    Correct answer is '1.23'. Can you explain this answer?
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    Reaction of x g of Sn with HCl quantitatively produced a salt. Entire ...
    Given information:
    - x g of Sn reacted quantitatively with HCl to produce a salt
    - The entire amount of the salt reacted with y g of nitrobenzene in the presence of required amount of HCl to produce 1.29 g of an organic salt (quantitatively)
    - Molar masses (in g mol-1) of H, C, N, O, Cl and Sn are 1, 12, 14, 16, 35 and 119, respectively

    To find: Value of y

    Solution:
    1. Finding the moles of Sn in x g of Sn:
    - Molar mass of Sn = 119 g/mol
    - Moles of Sn = mass/molar mass = x/119
    - Let's assume this value as 'a'

    2. Finding the moles of HCl required to react with 'a' moles of Sn:
    - From the balanced chemical equation of the reaction between Sn and HCl, we know that 1 mole of Sn reacts with 2 moles of HCl
    - So, 'a' moles of Sn will react with 2*a moles of HCl
    - Molar mass of HCl = 35 + 1 = 36 g/mol
    - Mass of HCl required = moles * molar mass = 2*a*36 = 72a
    - Let's assume this value as 'b'

    3. Finding the moles of the salt produced in step 2:
    - Since the reaction between Sn and HCl was quantitative, all the Sn reacted to form the salt
    - So, the moles of the salt produced will be equal to the moles of Sn used, which is 'a'

    4. Finding the moles of nitrobenzene required to react with 'a' moles of the salt:
    - From the given information, we know that the entire amount of the salt reacted with y g of nitrobenzene
    - Molar mass of nitrobenzene = 12*7 + 1*5 + 14 = 93 g/mol
    - Moles of nitrobenzene required = mass/molar mass = y/93
    - Let's assume this value as 'c'

    5. Finding the moles of the organic salt produced in step 4:
    - From the given information, we know that 1.29 g of the organic salt was produced
    - Molar mass of the organic salt is not given, so let's assume it as 'M'
    - Moles of the organic salt produced = mass/molar mass = 1.29/M
    - Let's assume this value as 'd'

    6. Writing the balanced chemical equation of the reaction between the salt and nitrobenzene:
    - Let's assume that the salt is SnCl2.X, where X represents the anion part of the salt
    - In the presence of HCl, the salt reacts with nitrobenzene to form an organic salt, which can be represented as:
    SnCl2.X + C6H5NO2 + HCl -> Organic salt + SnCl4 + H2O
    - Since the reaction was quantitative, all the salt reacted with nitrobenzene to form the organic salt

    7. Finding the moles of SnCl2 in the salt:
    - Let's assume that the molar mass
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    Community Answer
    Reaction of x g of Sn with HCl quantitatively produced a salt. Entire ...
    1 mole of organic salt is produced by 1 mole of nitrobenzene 0.01 mole of organic salt is produced by 0.01 mole nitrobenzene.
    Molar mass of nitrobenzene
    = 12 × 6 + 1 × 5 + 14 × 1 + 16 × 2
    = 72 + 5 + 14 + 32 = 123 g mol-1
    Mass of nitrobenzene required,
    y = moles of nitrobenzene × molar mass
    = 0.01 × 123 = 1.23 g
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    Reaction of x g of Sn with HCl quantitatively produced a salt. Entire amount of the salt reacted with y g of nitrobenzene in the presence of required amount of HCl to produce 1.29 g of an organic salt (quantitatively).(Use Molar masses (in g mol-1) of H, C, N, O, Cl and Sn as 1, 12, 14, 16, 35 and 119, respectively)Q. The value of y is _______.Correct answer is '1.23'. Can you explain this answer?
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    Reaction of x g of Sn with HCl quantitatively produced a salt. Entire amount of the salt reacted with y g of nitrobenzene in the presence of required amount of HCl to produce 1.29 g of an organic salt (quantitatively).(Use Molar masses (in g mol-1) of H, C, N, O, Cl and Sn as 1, 12, 14, 16, 35 and 119, respectively)Q. The value of y is _______.Correct answer is '1.23'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Reaction of x g of Sn with HCl quantitatively produced a salt. Entire amount of the salt reacted with y g of nitrobenzene in the presence of required amount of HCl to produce 1.29 g of an organic salt (quantitatively).(Use Molar masses (in g mol-1) of H, C, N, O, Cl and Sn as 1, 12, 14, 16, 35 and 119, respectively)Q. The value of y is _______.Correct answer is '1.23'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Reaction of x g of Sn with HCl quantitatively produced a salt. Entire amount of the salt reacted with y g of nitrobenzene in the presence of required amount of HCl to produce 1.29 g of an organic salt (quantitatively).(Use Molar masses (in g mol-1) of H, C, N, O, Cl and Sn as 1, 12, 14, 16, 35 and 119, respectively)Q. The value of y is _______.Correct answer is '1.23'. Can you explain this answer?.
    Solutions for Reaction of x g of Sn with HCl quantitatively produced a salt. Entire amount of the salt reacted with y g of nitrobenzene in the presence of required amount of HCl to produce 1.29 g of an organic salt (quantitatively).(Use Molar masses (in g mol-1) of H, C, N, O, Cl and Sn as 1, 12, 14, 16, 35 and 119, respectively)Q. The value of y is _______.Correct answer is '1.23'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
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