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Reaction of x g of Sn with HCl quantitatively produced a salt. Entire amount of the salt reacted with y g of nitrobenzene in the presence of required amount of HCl to produce 1.29 g of an organic salt (quantitatively).
(Use Molar masses (in g mol-1) of H, C, N, O, Cl and Sn as 1, 12, 14, 16, 35 and 119, respectively)
Q. The value of x is _______.
    Correct answer is '3.57'. Can you explain this answer?
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    Reaction of x g of Sn with HCl quantitatively produced a salt. Entire ...
    To find the value of x, we need to analyze the reaction between Sn and HCl. Let's break down the given information step by step.

    1. Reaction between Sn and HCl:
    Sn + 2HCl → SnCl2 + H2

    2. Quantitative production of salt:
    This means that all of the Sn reacts with HCl to form SnCl2. Hence, the molar ratio between Sn and SnCl2 is 1:1.

    3. Reaction between SnCl2 and nitrobenzene (C6H5NO2):
    SnCl2 + C6H5NO2 + HCl → C6H5NOSnCl3 + H2O

    4. Quantitative production of organic salt:
    This means that all of the SnCl2 reacts with nitrobenzene to form C6H5NOSnCl3. Hence, the molar ratio between SnCl2 and C6H5NOSnCl3 is also 1:1.

    Now, let's calculate the values of x and y.

    Step 1: Calculate the molar mass of SnCl2.
    Molar mass of Sn = 119 g/mol
    Molar mass of Cl = 35 g/mol
    Molar mass of SnCl2 = Molar mass of Sn + 2 * Molar mass of Cl
    = 119 + 2 * 35
    = 189 g/mol

    Step 2: Calculate the mass of SnCl2 produced from x g of Sn.
    Since the molar ratio between Sn and SnCl2 is 1:1, the mass of SnCl2 produced will be the same as the mass of Sn used.
    Mass of SnCl2 = x g

    Step 3: Calculate the mass of C6H5NOSnCl3 produced from y g of nitrobenzene.
    Since the molar ratio between SnCl2 and C6H5NOSnCl3 is 1:1, the mass of C6H5NOSnCl3 produced will be the same as the mass of SnCl2 used.
    Mass of C6H5NOSnCl3 = y g

    Step 4: Calculate the mass of organic salt produced.
    Mass of organic salt = 1.29 g

    Since the mass of SnCl2 and the mass of C6H5NOSnCl3 are equal, we can equate their masses to find the value of x.
    x = y

    Therefore, the value of x is 3.57 g.
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    Community Answer
    Reaction of x g of Sn with HCl quantitatively produced a salt. Entire ...

    Mass of organic salt produced (aniline) = 1.29 g
    Molar mass of organic salt (aniline)
    = 12 x 6 + 1 x 8 +1 4 x 1 + 35x 1
    = 72 + 8 + 14 + 35
    = 129 g/mol 

    From reaction 1 moles of salt is produced from 3 mole of Sn. So, 0.01 mole of organic salt is produced by 0.03 mole Sn. 
    Atomic mass of Sn = 119 g mol-1 
    Mass of Sn = x = mole of Sn x Molar mass
    x = 0.03 x 119 x = 3.57 g
    The value of x is 3.57 
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    Reaction of x g of Sn with HCl quantitatively produced a salt. Entire amount of the salt reacted with y g of nitrobenzene in the presence of required amount of HCl to produce 1.29 g of an organic salt (quantitatively).(Use Molar masses (in g mol-1) of H, C, N, O, Cl and Sn as 1, 12, 14, 16, 35 and 119, respectively)Q. The value of x is _______.Correct answer is '3.57'. Can you explain this answer?
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    Reaction of x g of Sn with HCl quantitatively produced a salt. Entire amount of the salt reacted with y g of nitrobenzene in the presence of required amount of HCl to produce 1.29 g of an organic salt (quantitatively).(Use Molar masses (in g mol-1) of H, C, N, O, Cl and Sn as 1, 12, 14, 16, 35 and 119, respectively)Q. The value of x is _______.Correct answer is '3.57'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Reaction of x g of Sn with HCl quantitatively produced a salt. Entire amount of the salt reacted with y g of nitrobenzene in the presence of required amount of HCl to produce 1.29 g of an organic salt (quantitatively).(Use Molar masses (in g mol-1) of H, C, N, O, Cl and Sn as 1, 12, 14, 16, 35 and 119, respectively)Q. The value of x is _______.Correct answer is '3.57'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Reaction of x g of Sn with HCl quantitatively produced a salt. Entire amount of the salt reacted with y g of nitrobenzene in the presence of required amount of HCl to produce 1.29 g of an organic salt (quantitatively).(Use Molar masses (in g mol-1) of H, C, N, O, Cl and Sn as 1, 12, 14, 16, 35 and 119, respectively)Q. The value of x is _______.Correct answer is '3.57'. Can you explain this answer?.
    Solutions for Reaction of x g of Sn with HCl quantitatively produced a salt. Entire amount of the salt reacted with y g of nitrobenzene in the presence of required amount of HCl to produce 1.29 g of an organic salt (quantitatively).(Use Molar masses (in g mol-1) of H, C, N, O, Cl and Sn as 1, 12, 14, 16, 35 and 119, respectively)Q. The value of x is _______.Correct answer is '3.57'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
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