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When an emf E = 7cos wt is applied across a circuit, the current is I = 5coswt. What is the power factor for the circuit?
- a)infinite
- b)3/4
- c)zero
- d)1
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
When an emf E = 7cos wt is applied across a circuit, the current is I ...
Since E and I are in the same phase.
Therefore, phase difference will be 0 and since power factor= cosx (where x= phase difference) and x =0
therefore, cos x or power factor will be =1
Therefore, phase difference will be 0 and since power factor= cosx (where x= phase difference) and x =0
therefore, cos x or power factor will be =1
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When an emf E = 7cos wt is applied across a circuit, the current is I ...
Power factor is defined as the ratio of the real power to the apparent power in an AC circuit. It is represented by the symbol cos φ, where φ is the phase angle between the voltage and current waveforms.
Given, emf E = 7cos wt and current I = 5coswt
Real power, P = EIcosφ
Apparent power, S = EI
Therefore, power factor, cosφ = P/S = EIcosφ/EI = cosφ
As the current waveform is in phase with the voltage waveform, the phase angle between them is zero. Hence, cosφ = 1.
Therefore, the correct option is (d) 1.
Given, emf E = 7cos wt and current I = 5coswt
Real power, P = EIcosφ
Apparent power, S = EI
Therefore, power factor, cosφ = P/S = EIcosφ/EI = cosφ
As the current waveform is in phase with the voltage waveform, the phase angle between them is zero. Hence, cosφ = 1.
Therefore, the correct option is (d) 1.
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