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Four successive members of the first row transition elements are listed below with their atomic no. Which of them is expected to have the highest third ionisation enthalpy?
- a)iron (Z=26)
- b)chromium(Z=24)
- c)vanadium(Z=23)
- d)manganese(Z=25)
Correct answer is option 'D'. Can you explain this answer?
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Four successive members of the first row transition elements are liste...
Explanation:
The third ionization enthalpy is the energy required to remove the third electron from an atom. This energy increases with increasing atomic number and decreasing atomic radius. The four successive members of the first row transition elements listed below are:
a) Iron (Z=26)
b) Chromium (Z=24)
c) Vanadium (Z=23)
d) Manganese (Z=25)
Reasoning:
Manganese (Z=25) is expected to have the highest third ionization enthalpy because of the following reasons:
- As we move from left to right in a period, the atomic radius decreases because the number of electrons in the outermost shell remains the same, but the number of protons in the nucleus increases. Therefore, the attraction between the electrons and the nucleus increases, pulling the electrons closer to the nucleus and decreasing the atomic radius.
- Manganese has the highest atomic number of the four elements, which means it has the most protons in its nucleus. This increases the attraction between the nucleus and the electrons, making it more difficult to remove the third electron.
- The electron configuration of manganese is [Ar] 3d5 4s2. The five 3d electrons provide more shielding from the nucleus than the two 4s electrons, making it easier to remove the first two electrons. However, removing the third electron requires breaking into the stable 3d5 configuration, which requires a large amount of energy.
Therefore, the correct answer is option D, manganese (Z=25), which is expected to have the highest third ionization enthalpy among the four given elements.
The third ionization enthalpy is the energy required to remove the third electron from an atom. This energy increases with increasing atomic number and decreasing atomic radius. The four successive members of the first row transition elements listed below are:
a) Iron (Z=26)
b) Chromium (Z=24)
c) Vanadium (Z=23)
d) Manganese (Z=25)
Reasoning:
Manganese (Z=25) is expected to have the highest third ionization enthalpy because of the following reasons:
- As we move from left to right in a period, the atomic radius decreases because the number of electrons in the outermost shell remains the same, but the number of protons in the nucleus increases. Therefore, the attraction between the electrons and the nucleus increases, pulling the electrons closer to the nucleus and decreasing the atomic radius.
- Manganese has the highest atomic number of the four elements, which means it has the most protons in its nucleus. This increases the attraction between the nucleus and the electrons, making it more difficult to remove the third electron.
- The electron configuration of manganese is [Ar] 3d5 4s2. The five 3d electrons provide more shielding from the nucleus than the two 4s electrons, making it easier to remove the first two electrons. However, removing the third electron requires breaking into the stable 3d5 configuration, which requires a large amount of energy.
Therefore, the correct answer is option D, manganese (Z=25), which is expected to have the highest third ionization enthalpy among the four given elements.
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Four successive members of the first row transition elements are liste...
Ionization energy is the amount of energy released when an electron is removed from a neutral or gaseous ion.
Atomic number of manganese is 25 and its electronic configuration is as follows.
1s²2s²2p63s²3p64s²3d5
So, when two electrons are removed then configuration of manganese becomes .
1s²2s²2p63s²3p64s03d5
Now, there are 5 electrons in 3d orbital and therefore, it is stable in nature due to half filled configuration of d orbital.
When another electron is removed then ionization energy will become exceptionally high because the 3d orbital is stable and thus high heat or energy has to be provided in order to remove an electron from it.
Atomic number of manganese is 25 and its electronic configuration is as follows.
1s²2s²2p63s²3p64s²3d5
So, when two electrons are removed then configuration of manganese becomes .
1s²2s²2p63s²3p64s03d5
Now, there are 5 electrons in 3d orbital and therefore, it is stable in nature due to half filled configuration of d orbital.
When another electron is removed then ionization energy will become exceptionally high because the 3d orbital is stable and thus high heat or energy has to be provided in order to remove an electron from it.
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Four successive members of the first row transition elements are listed below with their atomic no. Which of them is expected to have the highest third ionisation enthalpy?a)iron (Z=26)b)chromium(Z=24)c)vanadium(Z=23)d)manganese(Z=25)Correct answer is option 'D'. Can you explain this answer?
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Four successive members of the first row transition elements are listed below with their atomic no. Which of them is expected to have the highest third ionisation enthalpy?a)iron (Z=26)b)chromium(Z=24)c)vanadium(Z=23)d)manganese(Z=25)Correct answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Four successive members of the first row transition elements are listed below with their atomic no. Which of them is expected to have the highest third ionisation enthalpy?a)iron (Z=26)b)chromium(Z=24)c)vanadium(Z=23)d)manganese(Z=25)Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Four successive members of the first row transition elements are listed below with their atomic no. Which of them is expected to have the highest third ionisation enthalpy?a)iron (Z=26)b)chromium(Z=24)c)vanadium(Z=23)d)manganese(Z=25)Correct answer is option 'D'. Can you explain this answer?.
Four successive members of the first row transition elements are listed below with their atomic no. Which of them is expected to have the highest third ionisation enthalpy?a)iron (Z=26)b)chromium(Z=24)c)vanadium(Z=23)d)manganese(Z=25)Correct answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Four successive members of the first row transition elements are listed below with their atomic no. Which of them is expected to have the highest third ionisation enthalpy?a)iron (Z=26)b)chromium(Z=24)c)vanadium(Z=23)d)manganese(Z=25)Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Four successive members of the first row transition elements are listed below with their atomic no. Which of them is expected to have the highest third ionisation enthalpy?a)iron (Z=26)b)chromium(Z=24)c)vanadium(Z=23)d)manganese(Z=25)Correct answer is option 'D'. Can you explain this answer?.
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