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A bus starting from rest moves with a uniform acceleration of 0.1m/s for 2 minutes.find (a)the speed acquired. (b)the distance travelled.
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A bus starting from rest moves with a uniform acceleration of 0.1m/s f...
Calculations:
(a) Speed acquired:
(b) Distance travelled:
Equation for Position-Velocity Relation:
- Initial velocity (u) = 0 m/s
- Acceleration (a) = 0.1 m/s^2
- Time (t) = 2 minutes = 120 seconds
(a) Speed acquired:
- Using the equation v = u + at, where v is the final velocity:
- v = 0 + 0.1 x 120 = 12 m/s
- Therefore, the speed acquired by the bus is 12 m/s.
(b) Distance travelled:
- Using the equation s = ut + 0.5at^2, where s is the distance travelled:
- s = 0 x 120 + 0.5 x 0.1 x 120^2 = 720 m
- Therefore, the distance travelled by the bus is 720 m.
Equation for Position-Velocity Relation:
- The equation for position-velocity relation is given by:
- s = ut + 0.5at^2
- This equation describes the relationship between an object's position (s), initial velocity (u), acceleration (a), and time (t).
- It is derived from the equations of motion and is used to calculate the distance travelled by an object with a constant acceleration.
- The equation can be rearranged to find other variables such as final velocity (v) and time (t).
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A bus starting from rest moves with a uniform acceleration of 0.1m/s f...
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A bus starting from rest moves with a uniform acceleration of 0.1m/s for 2 minutes.find (a)the speed acquired. (b)the distance travelled. Related: Equation for Position - Velocity Relation?
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