A bus starting from rest moves with uniform acceleration of 0.1 metre ...
Initial velocity(u)="0m/s"
Accelaration(a)="0,1m/s-2"
Time="2 mins=60*2=120 secs"
Final velocity=?
v=u+at
v=0+(0.1)120
v=0+12
v=12m/s
i.e
Final Velocity="12m/s"
Distance(s)=v(v)-u(u)=2a
s=144-0=2(0.1)
s=144=0.2
s=1440=2
s=720m
Therefore,
(a)=12m/s
(b)=720m
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A bus starting from rest moves with uniform acceleration of 0.1 metre ...
Initial velocity=0 m/s
Acceleration=0.1m/s
Time=2minutes=120seconds
Final velocity=?
v=u+at
=0+0.1(120)
=0+12
=12
2as=v²-u²
2(0.1)s=12²-0²
0.2s=144-0
0.2s=144
s=144/0.2
s=720
So, speed acquired=12m/s
Distance travelled=720m
A bus starting from rest moves with uniform acceleration of 0.1 metre ...
Acceleration
The given problem states that a bus starts from rest and moves with a uniform acceleration of 0.1 meters per second square. To solve this problem, we need to find the speed acquired by the bus and the distance it travels in 2 minutes.
Conversion
First, let's convert the time from minutes to seconds. There are 60 seconds in a minute, so 2 minutes would be equal to 2 * 60 = 120 seconds.
Speed
To find the speed acquired by the bus, we can use the equation:
final speed = initial speed + (acceleration * time)
Since the bus starts from rest, the initial speed is 0. Plugging in the values, we get:
final speed = 0 + (0.1 * 120)
final speed = 12 meters per second
Therefore, the speed acquired by the bus is 12 meters per second.
Distance
To find the distance traveled by the bus, we can use the equation:
distance = (initial speed * time) + (0.5 * acceleration * time^2)
Again, the initial speed is 0. Plugging in the values, we get:
distance = (0 * 120) + (0.5 * 0.1 * 120^2)
distance = 0 + (0.5 * 0.1 * 14400)
distance = 720 meters
Therefore, the distance traveled by the bus is 720 meters.
Summary
In summary, the bus acquires a speed of 12 meters per second and travels a distance of 720 meters in 2 minutes with a uniform acceleration of 0.1 meters per second square.
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