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A car starting from rest moves with uniform acceleration of 0.1 meter/second for 4 min .find the speed and distance travel?
Most Upvoted Answer
A car starting from rest moves with uniform acceleration of 0.1 meter/...
U = 0m/s. Since the car started from rest
v =?
t = 240 seconds
a = 0.1m/s2
s=?
From the first equation of motion we get,
v = u + at
= 0 + 0.1m/s2 × 240s
= 24m/s
From the second equation of motion we get
s = ut + 1/2at2
= 0 × 240s + 1/2 × 0.1m/s2 × 240s×240s
= 2880m
v =?
t = 240 seconds
a = 0.1m/s2
s=?
From the first equation of motion we get,
v = u + at
= 0 + 0.1m/s2 × 240s
= 24m/s
From the second equation of motion we get
s = ut + 1/2at2
= 0 × 240s + 1/2 × 0.1m/s2 × 240s×240s
= 2880m
Community Answer
A car starting from rest moves with uniform acceleration of 0.1 meter/...
Given:
- Initial velocity (u) = 0 m/s (car starts from rest)
- Acceleration (a) = 0.1 m/s^2
- Time (t) = 4 min = 4 * 60 = 240 seconds
To find:
- Final velocity (v)
- Distance traveled (s)
Calculating Final Velocity (v):
We can use the formula of motion:
v = u + at
Given:
u = 0 m/s
a = 0.1 m/s^2
t = 240 seconds
Substituting these values in the formula:
v = 0 + (0.1 * 240)
v = 0 + 24
v = 24 m/s
Therefore, the final velocity of the car is 24 m/s.
Calculating Distance Traveled (s):
We can use the formula of motion:
s = ut + (1/2)at^2
Given:
u = 0 m/s
a = 0.1 m/s^2
t = 240 seconds
Substituting these values in the formula:
s = 0 * 240 + (1/2) * 0.1 * (240)^2
s = 0 + (1/2) * 0.1 * 57600
s = 0 + 0.05 * 57600
s = 0 + 2880
s = 2880 meters
Therefore, the distance traveled by the car is 2880 meters.
Summary:
- The car started from rest and moved with a uniform acceleration of 0.1 m/s^2 for 4 minutes (240 seconds).
- The final velocity of the car is 24 m/s.
- The distance traveled by the car is 2880 meters.
- Initial velocity (u) = 0 m/s (car starts from rest)
- Acceleration (a) = 0.1 m/s^2
- Time (t) = 4 min = 4 * 60 = 240 seconds
To find:
- Final velocity (v)
- Distance traveled (s)
Calculating Final Velocity (v):
We can use the formula of motion:
v = u + at
Given:
u = 0 m/s
a = 0.1 m/s^2
t = 240 seconds
Substituting these values in the formula:
v = 0 + (0.1 * 240)
v = 0 + 24
v = 24 m/s
Therefore, the final velocity of the car is 24 m/s.
Calculating Distance Traveled (s):
We can use the formula of motion:
s = ut + (1/2)at^2
Given:
u = 0 m/s
a = 0.1 m/s^2
t = 240 seconds
Substituting these values in the formula:
s = 0 * 240 + (1/2) * 0.1 * (240)^2
s = 0 + (1/2) * 0.1 * 57600
s = 0 + 0.05 * 57600
s = 0 + 2880
s = 2880 meters
Therefore, the distance traveled by the car is 2880 meters.
Summary:
- The car started from rest and moved with a uniform acceleration of 0.1 m/s^2 for 4 minutes (240 seconds).
- The final velocity of the car is 24 m/s.
- The distance traveled by the car is 2880 meters.
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A car starting from rest moves with uniform acceleration of 0.1 meter/second for 4 min .find the speed and distance travel?
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A car starting from rest moves with uniform acceleration of 0.1 meter/second for 4 min .find the speed and distance travel? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about A car starting from rest moves with uniform acceleration of 0.1 meter/second for 4 min .find the speed and distance travel? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A car starting from rest moves with uniform acceleration of 0.1 meter/second for 4 min .find the speed and distance travel?.
A car starting from rest moves with uniform acceleration of 0.1 meter/second for 4 min .find the speed and distance travel? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about A car starting from rest moves with uniform acceleration of 0.1 meter/second for 4 min .find the speed and distance travel? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A car starting from rest moves with uniform acceleration of 0.1 meter/second for 4 min .find the speed and distance travel?.
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