Class 9 Exam > Class 9 Questions > A car starting from rest moves with uniform a...
Start Learning for Free
A car starting from rest moves with uniform acceleration of 0.1 meter/second for 4 min .find the speed and distance travel?
Most Upvoted Answer
A car starting from rest moves with uniform acceleration of 0.1 meter/...
U = 0m/s. Since the car started from rest
v =?
t = 240 seconds
a = 0.1m/s2
s=?
From the first equation of motion we get,
v = u + at
= 0 + 0.1m/s2 × 240s
= 24m/s
From the second equation of motion we get
s = ut + 1/2at2
= 0 × 240s + 1/2 × 0.1m/s2 × 240s×240s
= 2880m
v =?
t = 240 seconds
a = 0.1m/s2
s=?
From the first equation of motion we get,
v = u + at
= 0 + 0.1m/s2 × 240s
= 24m/s
From the second equation of motion we get
s = ut + 1/2at2
= 0 × 240s + 1/2 × 0.1m/s2 × 240s×240s
= 2880m
Community Answer
A car starting from rest moves with uniform acceleration of 0.1 meter/...
Given:
- Initial velocity (u) = 0 m/s (car starts from rest)
- Acceleration (a) = 0.1 m/s^2
- Time (t) = 4 min = 4 * 60 = 240 seconds
To find:
- Final velocity (v)
- Distance traveled (s)
Calculating Final Velocity (v):
We can use the formula of motion:
v = u + at
Given:
u = 0 m/s
a = 0.1 m/s^2
t = 240 seconds
Substituting these values in the formula:
v = 0 + (0.1 * 240)
v = 0 + 24
v = 24 m/s
Therefore, the final velocity of the car is 24 m/s.
Calculating Distance Traveled (s):
We can use the formula of motion:
s = ut + (1/2)at^2
Given:
u = 0 m/s
a = 0.1 m/s^2
t = 240 seconds
Substituting these values in the formula:
s = 0 * 240 + (1/2) * 0.1 * (240)^2
s = 0 + (1/2) * 0.1 * 57600
s = 0 + 0.05 * 57600
s = 0 + 2880
s = 2880 meters
Therefore, the distance traveled by the car is 2880 meters.
Summary:
- The car started from rest and moved with a uniform acceleration of 0.1 m/s^2 for 4 minutes (240 seconds).
- The final velocity of the car is 24 m/s.
- The distance traveled by the car is 2880 meters.
- Initial velocity (u) = 0 m/s (car starts from rest)
- Acceleration (a) = 0.1 m/s^2
- Time (t) = 4 min = 4 * 60 = 240 seconds
To find:
- Final velocity (v)
- Distance traveled (s)
Calculating Final Velocity (v):
We can use the formula of motion:
v = u + at
Given:
u = 0 m/s
a = 0.1 m/s^2
t = 240 seconds
Substituting these values in the formula:
v = 0 + (0.1 * 240)
v = 0 + 24
v = 24 m/s
Therefore, the final velocity of the car is 24 m/s.
Calculating Distance Traveled (s):
We can use the formula of motion:
s = ut + (1/2)at^2
Given:
u = 0 m/s
a = 0.1 m/s^2
t = 240 seconds
Substituting these values in the formula:
s = 0 * 240 + (1/2) * 0.1 * (240)^2
s = 0 + (1/2) * 0.1 * 57600
s = 0 + 0.05 * 57600
s = 0 + 2880
s = 2880 meters
Therefore, the distance traveled by the car is 2880 meters.
Summary:
- The car started from rest and moved with a uniform acceleration of 0.1 m/s^2 for 4 minutes (240 seconds).
- The final velocity of the car is 24 m/s.
- The distance traveled by the car is 2880 meters.
Attention Class 9 Students!
To make sure you are not studying endlessly, EduRev has designed Class 9 study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Class 9.
|
Explore Courses for Class 9 exam
|
|
Top Courses for Class 9View all
A car starting from rest moves with uniform acceleration of 0.1 meter/second for 4 min .find the speed and distance travel?
Question Description
A car starting from rest moves with uniform acceleration of 0.1 meter/second for 4 min .find the speed and distance travel? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about A car starting from rest moves with uniform acceleration of 0.1 meter/second for 4 min .find the speed and distance travel? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A car starting from rest moves with uniform acceleration of 0.1 meter/second for 4 min .find the speed and distance travel?.
A car starting from rest moves with uniform acceleration of 0.1 meter/second for 4 min .find the speed and distance travel? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about A car starting from rest moves with uniform acceleration of 0.1 meter/second for 4 min .find the speed and distance travel? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A car starting from rest moves with uniform acceleration of 0.1 meter/second for 4 min .find the speed and distance travel?.
Solutions for A car starting from rest moves with uniform acceleration of 0.1 meter/second for 4 min .find the speed and distance travel? in English & in Hindi are available as part of our courses for Class 9.
Download more important topics, notes, lectures and mock test series for Class 9 Exam by signing up for free.
Here you can find the meaning of A car starting from rest moves with uniform acceleration of 0.1 meter/second for 4 min .find the speed and distance travel? defined & explained in the simplest way possible. Besides giving the explanation of
A car starting from rest moves with uniform acceleration of 0.1 meter/second for 4 min .find the speed and distance travel?, a detailed solution for A car starting from rest moves with uniform acceleration of 0.1 meter/second for 4 min .find the speed and distance travel? has been provided alongside types of A car starting from rest moves with uniform acceleration of 0.1 meter/second for 4 min .find the speed and distance travel? theory, EduRev gives you an
ample number of questions to practice A car starting from rest moves with uniform acceleration of 0.1 meter/second for 4 min .find the speed and distance travel? tests, examples and also practice Class 9 tests.
|
|
Explore Courses for Class 9 exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup