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The ratio of present ages of Seeta and Geeta is 8 : 9. The sum of their ages is 68. What will be the ratio of their ages after 10 years?
  • a)
    23 : 24                     
  • b)
    15 : 16                     
  • c)
    3 : 7
  • d)
    21 : 23                       
  • e)
    None of these
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
The ratio of present ages of Seeta and Geeta is 8 : 9. The sum of thei...
Let their present ages be 8x and 9x
therefore, 8x+9x=68
x=4
now their present age will be 32 and 36
after 10 years their age would be 42 and 46
therefore , 42/46 = 21/23
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Community Answer
The ratio of present ages of Seeta and Geeta is 8 : 9. The sum of thei...
Given:
- Ratio of Seeta's age to Geeta's age = 8 : 9
- Sum of their ages = 68

To find:
- Ratio of their ages after 10 years

Solution:

Let's assume Seeta's current age = 8x
Then Geeta's current age = 9x

According to the problem,
8x + 9x = 68
=> 17x = 68
=> x = 4

Therefore,
Seeta's current age = 8x = 8 × 4 = 32
Geeta's current age = 9x = 9 × 4 = 36

After 10 years,
Seeta's age will be = 32 + 10 = 42
Geeta's age will be = 36 + 10 = 46

Therefore, the ratio of their ages after 10 years = 42 : 46

Simplifying the ratio by dividing both numbers by 2, we get:

21 : 23

Hence, the correct answer is option (d) 21 : 23.
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The ratio of present ages of Seeta and Geeta is 8 : 9. The sum of their ages is 68. What will be the ratio of their ages after 10 years?a)23 : 24b)15 : 16c)3 : 7d)21 : 23e)None of theseCorrect answer is option 'D'. Can you explain this answer?
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